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## anonymous one year ago ***

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1. anonymous

binomial for this one $n=5,k=4,p=\frac{2}{3},1-p=\frac{1}{3}$

2. anonymous

there are 5 combinations of four days... do i just raise (2/3) to the fourth power?

3. anonymous

use $P(x=4)=\binom{5}{4}\left(\frac{2}{3}\right)^4\left(\frac{1}{3}\right)$

4. anonymous

ohhhh i see

5. anonymous

yeah 5 combinations of 4 days, and $$\frac{2}{3}$$ gets raised to the power of 4,

6. anonymous

but also one failure, so need the $$\frac{1}{3}$$ there as well

7. anonymous

got it. Thanks so much!

8. anonymous

yw

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