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anonymous
 one year ago
Is tension force equivalent to applied force?
anonymous
 one year ago
Is tension force equivalent to applied force?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So let's say there is a tension force of 360N acting on a 30kg object on a flat surface with no friction. Acceleration can be calculated using the newton's second law F=ma such that 360N=30kg(a) a=12/s^2

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2if the object is being pulled by a rope, then the force on the object and the tension in the rope are one and the same, yes with our usual assumption that the rope is massless

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The rope is indeed not very massless but I hope physicists are smart enough to account for everything elseXD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we assume the rope is massless so the problem will be easier

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Question: Where is gravity?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i forget why it is easier to assume rope is massless

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2flat surface and frictionless

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2The problem indicates to tension and friction, but gravity is there still.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2ah, yes, but it is acting orthogonal to motion so indeed you would have R = mg in the up down direction equalling zero

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2if the rope is not massless then the tension is greater the further away from the block you are pulling because that part of the rope is pulling the block and the rest of the rope in addition you will have a force downwards on the rope  gravity

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Because no friction, so that the box moves with constant velocity and total force is as shown.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Actually, I don't know, hehehe... I forgot all of my physics knowledge. @IrishBoy123 rely on you. :)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439468440385:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2@Loser66 if you are ever relying on me, you are in such trouble :)) lol!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 so my answer turns out wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I seem to have neglected the gravity... He says this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Fnet = ma Ft – Fg = ma 360 – m g = m a 360 – 30 x9.8 = 30 a a= 2.2 or 2 m/s2 upward

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the unbalanced force was 360 N as you all know it, Mass of the object being moved was 120kg gravity is 9.8m/s^2 Surface is frictionless Force of tension=360N which @IrishBoy123 had claimed as being equivalent to applied force to the object with a mass of 120kg

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2not sure which we are now discussing can you draw it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439472031159:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry basically 30kg object being applied 360N tension force acceleration of which is being looked for.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439472054470:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2cool. here the surface is horizontal and frictionless, so we don't have to worry about gravity

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2if the drawing is accurate, the solution is correct can you post the question or link it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You have neglected gravity which acts downward.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Fnet = ma Ft – Fg = ma 360 – m g = m a 360 – 30 x9.8 = 30 a a= 2.2 or 2 m/s2 upward

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*quoted from my teacher.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439472226663:dwthis is tensile force which is also applied force

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0means the object is being pulled

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2ok there is a context here which i am clearly missing i think you have this dw:1439472256031:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2but you mentioned a flat surface with no friction. that was the source of the confusion dw:1439472446011:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this force whether its tension or not is pretty irrelevant unless you are calculating deformation/stress/strain

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2until we see the actual question or a good drawing, we are just guessing ..... and i am no good at that :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"A mass of 30 kg is hauled upward by a rope. The tension in the rope is 360 N. What is the magnitude of the acceleration of the mass?"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry it was my faulty @IrishBoy123

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I guess I was mixed up with some other questions which posed "frictionless surface"
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