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anonymous

  • one year ago

f(x) = x2 - 16 and g(x) = x+4. Find F over G of and its domain

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  1. anonymous
    • one year ago
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    \[\frac{ f(x) }{ g(x) }\] is this what you mean?

  2. anonymous
    • one year ago
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    yeah

  3. anonymous
    • one year ago
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    \[\frac{ (x^2 -16) }{ (x+4) }\] you can factor the numerator in a way so as to get two expressions one of which will be (x+4) which will cancel out with the denominator

  4. anonymous
    • one year ago
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    so in other words (x+4)(?) = (x^2 - 16)

  5. anonymous
    • one year ago
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    4x and 16x^2 right

  6. anonymous
    • one year ago
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    im sorry i don't quite understand your expression can you write it out?

  7. anonymous
    • one year ago
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    im not getting it

  8. anonymous
    • one year ago
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    okay do you know how to factor \[(x^2-16)\]

  9. welshfella
    • one year ago
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    x^2 - 16 is the difference of 2 squares x^2 is a perfect square and so is 4

  10. welshfella
    • one year ago
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    have you factored something like that before?

  11. anonymous
    • one year ago
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    no

  12. anonymous
    • one year ago
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    are you familiar with the difference of squares method (its the way to factor expresions like these )

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  13. anonymous
    • one year ago
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    yeah but its a real number right

  14. anonymous
    • one year ago
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    basically it means that if your constant (in this case the 16) is a perfect square you can factor the expression by multiplying two expressions which's constant is the perfect square of your original constant

  15. anonymous
    • one year ago
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    okay im over complicating this XD

  16. anonymous
    • one year ago
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    okay do you know what \[\sqrt{16} = ?\]

  17. anonymous
    • one year ago
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    2*8

  18. anonymous
    • one year ago
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    umm no , what number squared equals 16

  19. anonymous
    • one year ago
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    256

  20. anonymous
    • one year ago
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    no thats 16 squared

  21. welshfella
    • one year ago
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    no what number when multiplied by itself equals 16 like 3 * 3 = 9 So 3 is the square root of 9.

  22. anonymous
    • one year ago
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    4

  23. welshfella
    • one year ago
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    right

  24. anonymous
    • one year ago
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    correct which means that \[\sqrt{16} = 4\] and because 4 is a whole number we call 16 a perfect square

  25. anonymous
    • one year ago
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    okay thanks

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