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anonymous

  • one year ago

Let and Find ( g o f)(­ -7)

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  1. anonymous
    • one year ago
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    |dw:1439474897144:dw|

  2. anonymous
    • one year ago
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    first find \[f(-7)=(-7)^2+6\] what do you get?

  3. dinamix
    • one year ago
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    (gof)(-7) = 1+ 8/45 cuz (gof)(x) = 1+(8/(x^2+6))

  4. anonymous
    • one year ago
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    actually that is not quite correct

  5. dinamix
    • one year ago
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    lol

  6. dinamix
    • one year ago
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    why ?

  7. dinamix
    • one year ago
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    solution is (gof)(-7) = 1+8/55 sorry for this mistake but i am sure for this

  8. SolomonZelman
    • one year ago
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    \(\large\displaystyle g(x)=\frac{x+8}{x}\) \(\large\displaystyle f(x)=x^2+6\) \(\large\displaystyle g^\circ f=g(f(x))=\frac{(x^2+6)+8}{(x^2+6)}\) \(\large\displaystyle g^\circ f=g(f(x))=\frac{8}{(x^2+6)}+1\)

  9. SolomonZelman
    • one year ago
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    then plug in -7 for x (I swear this italian keyboard stinks)

  10. anonymous
    • one year ago
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    lol

  11. dinamix
    • one year ago
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    i find it before u mate ;D

  12. anonymous
    • one year ago
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    @Dajala seems to have pulled a runner

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