What is the value of the x variable in the solution to the following system of equations? 2x + 2y = 6 x + 3y = −1 a. −2 b. 2 c. 5 d. −5

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What is the value of the x variable in the solution to the following system of equations? 2x + 2y = 6 x + 3y = −1 a. −2 b. 2 c. 5 d. −5

Mathematics
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Can someone please walk me through how to do this
first equation times 3 and second equation times -2 (2x + 2y = 6) × 3 (x + 3y = −1) × (-2) this will get you a new (but equivalent to the previous) system of equations. 6x + 6y = 18 -2x - 6y = 2 now add the equations and solve for x
So you just take one of the equations and multiply it to the other equation?

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first equation divide each term by 2
Would it be x+y=6 then?
I didnàt multiply equation times equation, all I did is that I multiplied each term in the equation times some number.... i did this for both of the equations, and choose the numbers by which to multiply in a way that would eliminate the y (since the variable you need is x).
So you would come up with 6x+6y= 18? for the first equation and -2x+-6=2?
-2x - 6y = 2 for the second equation, you meant (right ?)
Sorry yes thats what I meant
yes, that is what you inded come up with.
itàs ok...)
Now, add the equations
6x + 6y = 18 -2x - 6y = 2
Okay so it would be 4x + 18y = 20?
Oh wait 12y*
18y?
no, not 12. when you add 6 and -6 you get 6+(-6)=6-6=0 and so when you add 6y and -6y you get (6y)+(-6y)=??
Oh so it would be 4x = 20?
so x is?
5?
yes, that is correct!
Thank you so much! That makes a lot more sense now!
very nice to hear that... you are welcome!
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