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anonymous
 one year ago
racing car traveling with constant acceleration increases its speed from 10 m/s to 50 m/s over a distance of 60 m. How long does this take?
anonymous
 one year ago
racing car traveling with constant acceleration increases its speed from 10 m/s to 50 m/s over a distance of 60 m. How long does this take?

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2use: \(v^2 = u^2 + 2 a x\) to get 'a' then: \(v = u + at\) to get t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I had also done exactly like that but this can't give the appropriate answer

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2from (1) \(a= \frac{50^2  10^2}{2 \times 60} = 20m/s^2\) and (2) \(t = \frac{50  10}{20} = 2 s\) to be sure, check using final equation of motion: \(x = ut + \frac{1}{2}a t^2 = 10(2) + \frac{1}{2} (20) 2^2 = 60m \ \huge \checkmark\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm thanks brother...me too got the same answer but the book from which i isolated this question have 4s answer in it thats why i was just confirming it
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