anonymous
  • anonymous
simplify radical :) help me please
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\frac{ 1 }{ \sqrt[4]{72x^2y^5} }\]
anonymous
  • anonymous
\[\frac{ (x^2y^5)^3/4 }{ 2^(3/4)\sqrt{3} ^{}x^2y^5}\]
anonymous
  • anonymous
?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
that is the expanded form
anonymous
  • anonymous
how to expand?
anonymous
  • anonymous
pull out the square root you end up with 1/(72x^2y^5)^1/4 and expand from there
anonymous
  • anonymous
can you give me step by step :)
anonymous
  • anonymous
how to get the final answer ..
triciaal
  • triciaal
|dw:1439483838266:dw|
triciaal
  • triciaal
|dw:1439483893738:dw|
triciaal
  • triciaal
do you know how to find the prime factors of 72?
anonymous
  • anonymous
2.2.2.3.3?
welshfella
  • welshfella
exactly right
anonymous
  • anonymous
then ?
triciaal
  • triciaal
so the 4th root of 72 is not a rational number just use the rules of exponents above and apply to your question

Looking for something else?

Not the answer you are looking for? Search for more explanations.