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## anonymous one year ago In the following triangle, = 60. Find the values of the angles B and B', which solve this ambiguous case http://media.apexlearning.com/Images/200801/09/cf213ca3-b382-45ab-ac52-d2473fc03d56.gif A. B = 56.8 or B' = 123.2 B. B = 64.13 or B' = 115.87 C. B = 62.56 or B' = 117.44 D. B = 62.03 or B' = 117.97

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1. mathstudent55

Use the law of sines first.

2. anonymous

i could really use the help going thru this

3. anonymous

i think its is B.

4. mathstudent55

I have no idea what the answer is. First use the law of cosines to find angle B or B'. $$\large \dfrac{15.4}{\sin 60^o} = \dfrac{16}{\sin B'}$$ Use this to find B'. Then we'll continue.

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