tw101
  • tw101
What is the standard form of the equation of the circle x2 -4x + y2 + 6y + 4 = 0? I already have the beginning: x^2-4x+y^2+6y+4=0 X^2+y^2-4x+6y=-4 but im not sure how to go from there, this is new to me.
Mathematics
katieb
  • katieb
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triciaal
  • triciaal
good start now complete each square the x group and the y group the equation of the circle (x-h)^2 +( y-k)^2 = r^2 (h,k) is the center of the circle and r is the radius
triciaal
  • triciaal
|dw:1439486073611:dw|
triciaal
  • triciaal
do you know how to complete the square?

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triciaal
  • triciaal
|dw:1439486445990:dw|
tw101
  • tw101
Yes, the answer I got was (x-2)^2 (y+3)^2 Center: (2,6) Radius:3. Im so sorry i didnt realize that you replied @triciaal
tw101
  • tw101
whoops center is (2,-3)
tw101
  • tw101
almost didnt catch that haha

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