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tw101

  • one year ago

What is the standard form of the equation of the circle x2 -4x + y2 + 6y + 4 = 0? I already have the beginning: x^2-4x+y^2+6y+4=0 X^2+y^2-4x+6y=-4 but im not sure how to go from there, this is new to me.

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  1. triciaal
    • one year ago
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    good start now complete each square the x group and the y group the equation of the circle (x-h)^2 +( y-k)^2 = r^2 (h,k) is the center of the circle and r is the radius

  2. triciaal
    • one year ago
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    |dw:1439486073611:dw|

  3. triciaal
    • one year ago
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    do you know how to complete the square?

  4. triciaal
    • one year ago
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    |dw:1439486445990:dw|

  5. tw101
    • one year ago
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    Yes, the answer I got was (x-2)^2 (y+3)^2 Center: (2,6) Radius:3. Im so sorry i didnt realize that you replied @triciaal

  6. tw101
    • one year ago
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    whoops center is (2,-3)

  7. tw101
    • one year ago
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    almost didnt catch that haha

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