anonymous
  • anonymous
please help!
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
The lengths of two sides of a triangle are shown below: Side 1: 3x2 − 4x − 1 Side 2: 4x − x2 + 5 The perimeter of the triangle is 5x3 − 2x2 + 3x − 8. Part A: What is the total length of the two sides, 1 and 2, of the triangle? (4 points) Part B: What is the length of the third side of the triangle? (4 points) Part C: Do the answers for Part A and Part B show that the polynomials are closed under addition and subtraction? Justify your answer. (2 points)
welshfella
  • welshfella
Part A total length = 3x^2 - 4x - 1 + 4x - x^2 + 5
anonymous
  • anonymous
Thats the whole answer?

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anonymous
  • anonymous
anonymous
  • anonymous
3rd side is 5x^3
anonymous
  • anonymous
Thank you! Can you help me with part C please!
anonymous
  • anonymous
sure!
anonymous
  • anonymous
Thank you!
anonymous
  • anonymous
you need to use algebraic properties associative or commutative
anonymous
  • anonymous
Can you help please!
anonymous
  • anonymous
yeah, just a second. let me work it out. ok?
anonymous
  • anonymous
ok no problem :]
anonymous
  • anonymous
ok....see if this will help you...i had to type it in another program because it helps me with the math...
anonymous
  • anonymous
Side 1 = 8x² - 5x - 2 Side 2 = 7x - x² + 3 Perimeter, P = 4x³ - 3x² + 2x - 6 A. ) Length, L = Side 1 + Side 2 Subbing known values, L = 8x² - 5x - 2 + 7x - x² + 3 L = 8x² - x² - 5x + 7x - 2 + 3 L = 7x² + 2x + 1 Total Length of Two Sides = 7x² + 2x + 1 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ B.) Third Side, S = P - Side 1 - Side 2 Subbing, S = 4x³ - 3x² + 2x - 6 - (8x² - 5x - 2) - (7x - x² + 3) S = 4x³ - 3x² + 2x - 6 - 8x² + 5x + 2 - 7x + x² - 3 S = 4x³ - 3x² - 8x² + x² + 2x + 5x - 7x - 6 + 2 - 3 S = 4x³ - 10x² - 7 Third Side = 4x³ - 10x² - 7 ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ C.) Adding or subtracting the polynomials yields polynomials so they are closed under addition and subtraction.
anonymous
  • anonymous
Okay thank you so much!
anonymous
  • anonymous
wait...i might of did that wrong... wait...does your question have answers? or do you have to make them?
anonymous
  • anonymous
I ahve to type them.
anonymous
  • anonymous
oh...ok well i hope this helps...and i hope it is right...im pretty positive they are...

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