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HelloKitty17

  • one year ago

A punter kicks a football upward with an initial speed of 48 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt - 16t2 where h represents height in feet and r represents the initial speed. Numerical Answers Expected!

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  1. HelloKitty17
    • one year ago
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    @MeganChase @jcoury @OregonDuck

  2. OregonDuck
    • one year ago
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    h = 0 when it hits the ground, therefore: -16t^2 + 48t = 0 --------------------------------------... Factor out -16t -16t(t + 3) = 0 : Two solutions t = 0, when it begins it's upward journey and t = 3 sec, when it returns to earth

  3. welshfella
    • one year ago
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    when the ball hits the ground h = 0 so we have 0 = 48t - 16t^2 solve for t one of the solutions will be 0 corresponding to start of the kick The other one will be you answer.

  4. OregonDuck
    • one year ago
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    so 3 is the answer

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