One solution of the equation 2x2 - x - 10 = 0 is five over two. What is the other solution?
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factor the above by grouping
If you start with 2x2 − x − 10 = 0 and divide everything by 2 to make the leading coefficient 1, you get x^2-(1/2)x-5 = 0
Now it turns out that for something like x^2+bx+c = 0, the two roots/solutions p and q multiply to the last coefficient c. In other words, pq = c
Since one root is 5/2, we know that (5/2)q = -5
Now solve for q to get q = -10/5 = -2
So the other root is -2
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