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anonymous

  • one year ago

f(x) = quantity x squared plus x minus two divided by quantity x squared minus three x minus four A coordinate axis scaled by one. Domain and Range (1 point): _____________________ x and y Intercept(s) (1 point): _____________________ Horizontal Asymptote(s) (1 point): ___________________ Vertical Asymptote(s) (1 point): ____________________

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  1. e.mccormick
    • one year ago
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    What were you having trouble with?

  2. anonymous
    • one year ago
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    f(x)=x^2+x-2/x^2-3x-4

  3. anonymous
    • one year ago
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    Those four questions

  4. welshfella
    • one year ago
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    factoring the top and bottom would be of help

  5. e.mccormick
    • one year ago
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    Yes, I see it as \(f(x) = \frac{x^2+x-2}{x^2-3x-4}\) Do you understand what the questions are asking for or, are you just not sure of the process to get those answers? Just trying to find out what issue needs to be addressed.

  6. anonymous
    • one year ago
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    Idk the process

  7. e.mccormick
    • one year ago
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    The domain is the valid inputs. The range is the valid outputs. Because it is a quotent or fraction, anything that would make the bottom of the fraction into 0 is undefined. So you need to look for what would make the bottom 0. That is why welshfella talked about facotring the bottom. That also has to do with vertical asmptotes.

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