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anonymous

  • one year ago

What is the solution of the system of equations? y = –2x + 5 y = –2x + 20

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  1. anonymous
    • one year ago
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    no solution (1, 3) (0, 20) infinitely many solutions

  2. pooja195
    • one year ago
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    Use substituion we already know the value of y right? Plug E1 into E2 -2x+5= –2x + 20 solve for x

  3. anonymous
    • one year ago
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    so is it like this -2(2)+5 = _2(2)+20

  4. pooja195
    • one year ago
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    Well you cant solve the equation :) Add 2x to both sides. −2x+5+2x=−2x+20+2x 5=20 Subtract 5 from both sides. 5−5=20−5 0=15

  5. anonymous
    • one year ago
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    sorry but I don't get it

  6. pooja195
    • one year ago
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    Ok when you have m=m <---meaning 2 of the SAME numbers equaling each other it means that there are infinite solutions m=1 <-----one solutions m=n <---No solutions

  7. pooja195
    • one year ago
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    in this case once we solve \[\huge~\rm~-2x+5= –2x + 20 \] We get 0=15 therefore there are no solutions to this system of equations

  8. anonymous
    • one year ago
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    oh okay

  9. pooja195
    • one year ago
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    Do you understand?

  10. anonymous
    • one year ago
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    yes I understood a bit, thanks

  11. pooja195
    • one year ago
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    Let me know if anything is unclear :) And your welcome :)

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