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anonymous
 one year ago
helpppppp
anonymous
 one year ago
helpppppp

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ik its choice a and b but ineed the restriction?

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{x^2+4x45}{x^2+10x+9}=\frac{x5}{x+1}\]

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The first step is to factor the numerator and denominator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the restriction 9

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.1\[\mathrm{Factor}\:x^2+4x45:\quad \left(x+9\right)\left(x5\right)\] \[=\frac{\left(x+9\right)\left(x5\right)}{x^2+10x+9}\] \[\mathrm{Factor}\:x^2+10x+9:\quad \left(x+9\right)\left(x+1\right)\] \[=\frac{\left(x+9\right)\left(x5\right)}{\left(x+9\right)\left(x+1\right)}\] \[=\frac{\left(x+9\right)\left(x5\right)}{\left(x+9\right)\left(x+1\right)}\] \[\mathrm{Cancel\:the\:common\:factors:}\:x+9\] \[=\frac{x5}{x+1}\] that is the answer

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.1@jammy987 are you understand

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439493910772:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0you do not want factor to be 0 so restrictions are the values that will make the factor = 0

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0restrictions x not = 1, not = 5, not = 9

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0so option A is correct do not divide by 0

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0You don't want the denominator to be zero. The numerator can be zero. These two factors cannot be zero: \(x + 9 \ne 0\) \(x + 1 \ne 0\) x  5 .can be zero because a zero in the numerator is permitted.
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