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@LexiLuvv2431 The true statement in that a tangent is positive in quadrant I.

tangent is positive in first quadrant

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remember the \(\huge\color{green}{\rm CAST }\) rule

Thank you guys so much I have a few more can you guys help?

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@LexiLuvv2431 u have ta give me da medal because I answerd it 1 lol

Find the sine, cosine, and tangent of 120 degrees. and I did lol

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so cos= ?
sin=?
tan = ?

Sin is \[\frac{ \sqrt{3} }{ 2 }\]

Idk the others though

waittt okay so then would the cos equal 1/2 and the tan equal \[\sqrt{3}\] ?

cos is not just 1/2 look at first drawing i posted above
cos is negative in which quadrant ?

Quadrant S

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cos is negative in 2nd and 3rd quadrant

Noo sorry this is soo confusing for me.

just focus on it
it's not hard you don't have to solve for anything
just read the unit circle

Ohhhh I seee. I get it nowww

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it's like simple (x,y) graph

(x,y)
x= cos
y=sin
so what is sin and cos in that equation ?

-3 and 1??

yew which one is cos

-3

cos = negative (-3) and sin =positive (1) hint!

Quadrant 2

yep right !!

a=1
b=-3
solve for c

100?

hmm 100 no how did you get that ?

ohhh I forgot the 3 was negative.
So -64

show your work how did you get that ?

okay \[(1)+(-3)^2=c^2\] when you take even power of negative you will get positive answer

and i just noticed you said 100 earlier

wait no nvm

Okay now I'm confused

10 squared is 100

square root
not square

Okay I have no idea how to do this part

\[\huge\rm \sqrt{c^2}= \sqrt{10}\]take square root both sides
sqrt{c^2} = c so \[c =\sqrt{10}\]

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Okayy I see

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opp= opposite side of theta
adj= adjacent of theta
hyp=hypotenuse of theta

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So is the answer finished?

yes right just write value of sin cosine and tan

How do I do that?

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Thank youu so much

my pleasure:)