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anonymous

  • one year ago

I'm not sure I completely understand why the following differential / integral manipulation is mathematically correct.

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  1. anonymous
    • one year ago
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    \[\int\limits_{0}^{t}L \frac{ di(t) }{ dt } i(t) dt = \int\limits_{0}^{i(t)}L i(t) di(t) \]

  2. anonymous
    • one year ago
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    What I don't understand is why the upper bound is i(t) and not t while the right and left hand side of the equation remain equivalent.

  3. anonymous
    • one year ago
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    This is from an electrical engineering book. Thus i(t) is the current as a function of time, thus t > 0

  4. anonymous
    • one year ago
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    I'm thinking it might be u-substitution

  5. anonymous
    • one year ago
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    \[u=i(t)\] \[du=\frac{ di(t) }{ dt }di(t)\] then change the limits

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