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anonymous
 one year ago
I'm not sure I completely understand why the following differential / integral manipulation is mathematically correct.
anonymous
 one year ago
I'm not sure I completely understand why the following differential / integral manipulation is mathematically correct.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{t}L \frac{ di(t) }{ dt } i(t) dt = \int\limits_{0}^{i(t)}L i(t) di(t) \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What I don't understand is why the upper bound is i(t) and not t while the right and left hand side of the equation remain equivalent.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is from an electrical engineering book. Thus i(t) is the current as a function of time, thus t > 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm thinking it might be usubstitution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[u=i(t)\] \[du=\frac{ di(t) }{ dt }di(t)\] then change the limits
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