anonymous
  • anonymous
Explain the difference between using the trigonometric ratios (sin, cos, tan) to solve for a missing angle in a right triangle versus using the reciprocal ratios (sec, csc, cot). You must use complete sentences and any evidence needed (such as an example) to prove your point of view. @hero
Geometry
chestercat
  • chestercat
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anonymous
  • anonymous
Can anyone please help me!!
anonymous
  • anonymous
Nnesha
  • Nnesha
they are reciprocal not much difference |dw:1439497598541:dw| \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

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Nnesha
  • Nnesha
so if sin = opposite over hyp csc = hyp over adjacent
anonymous
  • anonymous
Thanks! Wait how do I award medals?
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click on the blue button *best Response*
Nnesha
  • Nnesha
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anonymous
  • anonymous
Thanks lol:)))
Nnesha
  • Nnesha
my pleasure.

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