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anonymous
 one year ago
Explain the difference between using the trigonometric ratios (sin, cos, tan) to solve for a missing angle in a right triangle versus using the reciprocal ratios (sec, csc, cot). You must use complete sentences and any evidence needed (such as an example) to prove your point of view.
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anonymous
 one year ago
Explain the difference between using the trigonometric ratios (sin, cos, tan) to solve for a missing angle in a right triangle versus using the reciprocal ratios (sec, csc, cot). You must use complete sentences and any evidence needed (such as an example) to prove your point of view. @hero

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can anyone please help me!!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1they are reciprocal not much difference dw:1439497598541:dw \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so if sin = opposite over hyp csc = hyp over adjacent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! Wait how do I award medals?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1click on the blue button *best Response*

Nnesha
 one year ago
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