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anonymous
 one year ago
What is the equation in pointslope form of the line passing through (4, 0) and (2, 6)?
anonymous
 one year ago
What is the equation in pointslope form of the line passing through (4, 0) and (2, 6)?

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Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1do you know the slope formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, but the options for my answer are really confusing me they are: y = 4x − 2 y = 2x − 4 y = −3(x − 4) y = 3(x + 4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i keep getting y = 3x + 12

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1do you know how to use distributive property?

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1do you know the distributive property?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wow i feel so stupid, its y= 3 (x4)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1haha yes that's correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks! can i ask one more question please?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you solve this problem? Solve the following for y: −6x + 2y = 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes y = −6x + 8 y = 6x + 8 y = −3x + 4 y = 3x + 4

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.1\(6x+2y=8\) first you want to move 6x to move it, you add +6x that gives you \(2y=8+6x\) next you want to isolate y and get rid of 2 to do that, divide 2 by each number 2/2 = 0 8/2=4 6x/2=3x \(y=4+3x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok that makes sense now . Thanks for all your help! much appreciated

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can i ask you one more question then?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nevermind, thans for your help again!
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