Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

okay so i'v done this a couple of times but i keep getting the wrong answer.

then add all trapezoids.

Dont wonder the area is negative, that is because the entire thing is under the x-axis.

yep im getting the same answer i was getting before , still wrong

these are my answer choices
–12.727
–11.546
–16.273
–13.909

@SolomonZelman you still there ?

yes, i am here. I am just glitching outside the US a little.

what did you get when you added the trapezoids?

153, i did the same thing but by taking the left point and right point sum and averaging them

i get -153 doing a completely valid method.... maybe your table has typos?

@ganeshie8 any idea?

\[\frac{1}{b-a} \int\limits _a^b f(x) dx\]

The average function value formula is:|dw:1439414018001:dw|

is average value of a function on interval [a,b]

oh the area, sorry....

the average is what they need...

so you made it this far:
\[\frac{1}{15-4} \int\limits_4^{16} f(x) dx \\ \frac{1}{15-4}(-153)\]

yes that 16 is suppose to be a 15

well -13.909 but yah

yep , my bad .

you should give @solomonzelman a medal he did the harder part of the problem