Write an equation of a line perpendicular to y =1/4 x + 4 in slope-intercept form that passes through the point (-2, 6).
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from the equation
y=1/4 x +4
what is the slope of that line?
(hint: In the form y=mx+b : m is the slope)
the slope is 1/4 so the new slope would be -4
im having trouble on how to find the b of the new equation
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@MrNood do you know how to do that
ok so you have the new slope so the equation of th enew line would be
y = -4x + b
but you know that the point (-2,6) lies on the line
so when x=-2 y= 6
so put those 2 numbers in the equation = and you will find b
6 = -4 * -2 + b
6 = 8 + b
b = -2
Is that right @MrNood
check it by putting it back into the equation ....
(it looks right to me...)