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mathmath333

  • one year ago

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  1. mathmath333
    • one year ago
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    In a lottery, a person choses six different natural numbers at random from 1 to 20, and if these six numbers match with the six numbers already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game?

  2. anonymous
    • one year ago
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    Well, for the first number, there would be 20 number choices. For the second, there would be 19. For the third there would be 18. You get the pattern, right?

  3. mathmath333
    • one year ago
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    20!

  4. Vocaloid
    • one year ago
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    uh, not quite, there are only 6 numbers on the ticket following jf04's logic, we see that first number --> 20 choices second number --> 19 choices, etc. we stop when we get to the sixth number, giving us: 20*19*18*17*16*15 so our probability is 1/(20*19*18*17*16*15)

  5. mathmath333
    • one year ago
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    ok thnks

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