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anonymous
 one year ago
ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month than the month before. She ended up saving $19,779.00. How much more did she save each month?
anonymous
 one year ago
ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month than the month before. She ended up saving $19,779.00. How much more did she save each month?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you think? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm thinking the final amount is the sum of an arithmetic series and they want you to find the common difference of the sequence

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I just dont know how to do it hahah

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use this one to find \(a_{57}\), the amount saved in the 57th month. \[S_{57}=\frac{ n }{ 2 }(a_1+a_{57})\] n = 57 and \(a_1=11\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so s57=28.5(11+a57)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right and S_57 = 19779

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solve for \(a_{57}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What would I divide by?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's the 57th term. This is the formula to find d\[a_n=a_1+d(n1)\] \[683=11+d(571)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But the answer choices are 11.00 11.50 12.00 12.50

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks :) If I open anothe question, will u answer it?
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