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anonymous

  • one year ago

ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month than the month before. She ended up saving $19,779.00. How much more did she save each month?

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  1. anonymous
    • one year ago
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    @phi

  2. anonymous
    • one year ago
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    @peachpi

  3. anonymous
    • one year ago
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    What do you think? :)

  4. anonymous
    • one year ago
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    I'm thinking the final amount is the sum of an arithmetic series and they want you to find the common difference of the sequence

  5. anonymous
    • one year ago
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    I agree!

  6. anonymous
    • one year ago
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    But I just dont know how to do it hahah

  7. anonymous
    • one year ago
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    Use this one to find \(a_{57}\), the amount saved in the 57th month. \[S_{57}=\frac{ n }{ 2 }(a_1+a_{57})\] n = 57 and \(a_1=11\)

  8. anonymous
    • one year ago
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    ok so s57=28.5(11+a57)

  9. anonymous
    • one year ago
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    Right and S_57 = 19779

  10. anonymous
    • one year ago
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    now what do we do?

  11. anonymous
    • one year ago
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    solve for \(a_{57}\)

  12. anonymous
    • one year ago
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    What would I divide by?

  13. anonymous
    • one year ago
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    28.5

  14. anonymous
    • one year ago
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    694

  15. anonymous
    • one year ago
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    subtract 11

  16. anonymous
    • one year ago
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    683

  17. anonymous
    • one year ago
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    that's the 57th term. This is the formula to find d\[a_n=a_1+d(n-1)\] \[683=11+d(57-1)\]

  18. anonymous
    • one year ago
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    683=57d-d+11

  19. anonymous
    • one year ago
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    11.78=answer

  20. anonymous
    • one year ago
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    But the answer choices are 11.00 11.50 12.00 12.50

  21. anonymous
    • one year ago
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    683=11 + 56d

  22. anonymous
    • one year ago
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    672 = 56d

  23. anonymous
    • one year ago
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    12:)

  24. anonymous
    • one year ago
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    yes

  25. anonymous
    • one year ago
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    Thanks :) If I open anothe question, will u answer it?

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