anonymous
  • anonymous
ennifer has been saving for college for 57 months. The first month, she saved $11. She was able to save more money each month than the month before. She ended up saving $19,779.00. How much more did she save each month?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@phi
anonymous
  • anonymous
@peachpi
anonymous
  • anonymous
What do you think? :)

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anonymous
  • anonymous
I'm thinking the final amount is the sum of an arithmetic series and they want you to find the common difference of the sequence
anonymous
  • anonymous
I agree!
anonymous
  • anonymous
But I just dont know how to do it hahah
anonymous
  • anonymous
Use this one to find \(a_{57}\), the amount saved in the 57th month. \[S_{57}=\frac{ n }{ 2 }(a_1+a_{57})\] n = 57 and \(a_1=11\)
anonymous
  • anonymous
ok so s57=28.5(11+a57)
anonymous
  • anonymous
Right and S_57 = 19779
anonymous
  • anonymous
now what do we do?
anonymous
  • anonymous
solve for \(a_{57}\)
anonymous
  • anonymous
What would I divide by?
anonymous
  • anonymous
28.5
anonymous
  • anonymous
694
anonymous
  • anonymous
subtract 11
anonymous
  • anonymous
683
anonymous
  • anonymous
that's the 57th term. This is the formula to find d\[a_n=a_1+d(n-1)\] \[683=11+d(57-1)\]
anonymous
  • anonymous
683=57d-d+11
anonymous
  • anonymous
11.78=answer
anonymous
  • anonymous
But the answer choices are 11.00 11.50 12.00 12.50
anonymous
  • anonymous
683=11 + 56d
anonymous
  • anonymous
672 = 56d
anonymous
  • anonymous
12:)
anonymous
  • anonymous
yes
anonymous
  • anonymous
Thanks :) If I open anothe question, will u answer it?

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