anonymous
  • anonymous
The graph of an equation is shown below: line joining ordered pairs negative 3,2 and 1, negative 2 Based on the graph, which of the following represents a solution to the equation?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
(–2,–3) (2, 1) (1, 2)I think its this one but im not sure (–3, 2)
Mehek14
  • Mehek14
can you attach a graph?
anonymous
  • anonymous
http://clay.flvs.net/webdav/assessment_images/educator_algebra1/v17/module05/module5_graph19.gif

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@mehek14
Mehek14
  • Mehek14
can't open
triciaal
  • triciaal
given 2 points on a line you can find the slope change in y divided by the change in x the slope is the same for any 2 points on that line using one of the given points the calculated slope and any point (x, y) you can rewrite the general equation match your equation with the options
triciaal
  • triciaal
|dw:1439673193120:dw|
triciaal
  • triciaal
this will find the equation of the graph the original question is not complete. it is asking for a solution to the equation.

Looking for something else?

Not the answer you are looking for? Search for more explanations.