A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
m1c1T1=m2C2T2 Help please?
anonymous
 one year ago
m1c1T1=m2C2T2 Help please?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have the given information, I need help setting up the problem!

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.3The regular formula is: q = m x C x (Tf  Ti) Where: q = amount of heat energy gained or lost by substance m = mass of sample C = heat capacity (J oC1 g1 or J K1 g1) T = temperature in Celsius q lost= q gained m x C x (Tf  Ti) = m x C x (Tf  Ti)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0\[m_1C_1T_1 = m_2C_2T_2\] solving for \(m_2\)\[m_2 = \frac{m_1C_1T_1}{C_2T_2}\] or, solving for \(C_2\)\[C_2 = \frac{m_1C_1T_1}{m_2T_2}\] or, solving for \(T_2\)\[T_2 = \frac{m_1C_1T_1}{m_2C_2}\]

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.3m1c1T1=m2C2T2 m1 is your mass of copper c1 is the specific heat capacity for copper (which is what you want to find) T1 will be the change in temperature for the copper (final temperature minus initial temperature) m2 is mass of water c2 is the specific heat for water (4.18) T2 is the change in temperature for the water (final temperature minus initial temperature)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@taramgrant0543664 Thanks that helps a ton! just one last question, how would i rearrange the formula to get C1?

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.3So to get c1 by itself you just divide by m1T1 and if you do it on one side you do it to the other so c1= (m2c2T2) / (m1T1) Sorry I'm on my iPad I don't have that fancy equation stuff on here or it would look nicer but I think it gets the point across let me know though if you don't understand!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I got it thanks :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.