A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

m1c1T1=m2C2T2 Help please?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I have the given information, I need help setting up the problem!

  2. taramgrant0543664
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    The regular formula is: q = m x C x (Tf - Ti) Where: q = amount of heat energy gained or lost by substance m = mass of sample C = heat capacity (J oC-1 g-1 or J K-1 g-1) T = temperature in Celsius q lost= q gained m x C x (Tf - Ti) = m x C x (Tf - Ti)

  3. UnkleRhaukus
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[m_1C_1T_1 = m_2C_2T_2\] solving for \(m_2\)\[m_2 = \frac{m_1C_1T_1}{C_2T_2}\] or, solving for \(C_2\)\[C_2 = \frac{m_1C_1T_1}{m_2T_2}\] or, solving for \(T_2\)\[T_2 = \frac{m_1C_1T_1}{m_2C_2}\]

  4. taramgrant0543664
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    m1c1T1=m2C2T2 m1 is your mass of copper c1 is the specific heat capacity for copper (which is what you want to find) T1 will be the change in temperature for the copper (final temperature minus initial temperature) m2 is mass of water c2 is the specific heat for water (4.18) T2 is the change in temperature for the water (final temperature minus initial temperature)

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @taramgrant0543664 Thanks that helps a ton! just one last question, how would i rearrange the formula to get C1?

  6. taramgrant0543664
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    So to get c1 by itself you just divide by m1T1 and if you do it on one side you do it to the other so c1= (m2c2T2) / (m1T1) Sorry I'm on my iPad I don't have that fancy equation stuff on here or it would look nicer but I think it gets the point across let me know though if you don't understand!

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay I got it thanks :)

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.