## anonymous one year ago m1c1T1=m2C2T2 Help please?

1. anonymous

I have the given information, I need help setting up the problem!

2. taramgrant0543664

The regular formula is: q = m x C x (Tf - Ti) Where: q = amount of heat energy gained or lost by substance m = mass of sample C = heat capacity (J oC-1 g-1 or J K-1 g-1) T = temperature in Celsius q lost= q gained m x C x (Tf - Ti) = m x C x (Tf - Ti)

3. UnkleRhaukus

$m_1C_1T_1 = m_2C_2T_2$ solving for $$m_2$$$m_2 = \frac{m_1C_1T_1}{C_2T_2}$ or, solving for $$C_2$$$C_2 = \frac{m_1C_1T_1}{m_2T_2}$ or, solving for $$T_2$$$T_2 = \frac{m_1C_1T_1}{m_2C_2}$

4. taramgrant0543664

m1c1T1=m2C2T2 m1 is your mass of copper c1 is the specific heat capacity for copper (which is what you want to find) T1 will be the change in temperature for the copper (final temperature minus initial temperature) m2 is mass of water c2 is the specific heat for water (4.18) T2 is the change in temperature for the water (final temperature minus initial temperature)

5. anonymous

@taramgrant0543664 Thanks that helps a ton! just one last question, how would i rearrange the formula to get C1?

6. taramgrant0543664

So to get c1 by itself you just divide by m1T1 and if you do it on one side you do it to the other so c1= (m2c2T2) / (m1T1) Sorry I'm on my iPad I don't have that fancy equation stuff on here or it would look nicer but I think it gets the point across let me know though if you don't understand!

7. anonymous

okay I got it thanks :)