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anonymous
 one year ago
Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. He will get a second turn if he rolls a sum that is an even number less than 10.
What are Henry's chances of getting a second turn when he rolls the number cubes?
7/18
11/18
5/36
17/36
I got 5/18. I added up the amount of different ways to get 28. I found 10. Either the test is wrong or I'm really bad at counting, and I'm not confident enough to count either of them out.
anonymous
 one year ago
Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. He will get a second turn if he rolls a sum that is an even number less than 10. What are Henry's chances of getting a second turn when he rolls the number cubes? 7/18 11/18 5/36 17/36 I got 5/18. I added up the amount of different ways to get 28. I found 10. Either the test is wrong or I'm really bad at counting, and I'm not confident enough to count either of them out.

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lucaz
 one year ago
Best ResponseYou've already chosen the best response.0only less than? not 'less than or equal to' ?

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1The sample space has 36 possible combinations of numbers. These can be set out in column form as follows: 6,6 5,6 4,6 3,6 2,6 1,6 6,5 5,5 4,5 3,5 2,5 1,5 6,4 5,4 4,4 3,4 2,4 1,4 6,3 5,3 4,3 3,3 2,3 1,3 6,2 5,2 4,2 3,2 2,2 1,2 6,1 5,1 4,1 3,1 2,1 1,1 I get 1 in the first row, 2 in the second row, 2 in the third row, 3 in the fourth row, 3in the fifth row and 3 in the sixth row.

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1That makes 14 pairs out of 36 possible pairings.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know if the count duplicates, like 4+2 and 2+4. I didn't.

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1Yes, 4+2 and 2 + 4 are counted. Strictly they are not duplicates, the reason being the order is reversed.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Thank you! I've taken a test twice now (this is my last chance), and both times I got this type of question wrong. Thank you for your help!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It was correct! Thank you again!

kropot72
 one year ago
Best ResponseYou've already chosen the best response.1You're welcome :) Hint: Remember to simplify the fraction.
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