help plz for medaal

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

help plz for medaal

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I see a figure, but I don;t see a question.
Find the area of the following shape. You must show all work to receive credit.
Your polygon looks like this. |dw:1439511583508:dw|
yes
Separate it into smaller well-known shapes and find their areas. Then add up all the areas. By well-known shapes I mean triangles and a rectangle.
can u walk and help me through it
|dw:1439511729134:dw|
ok
Look above. I divided the shape into 4 triangles and a rectangle.
ok i see
|dw:1439511826496:dw|
Let's start with the rectangle.
|dw:1439511982395:dw|
Notice the height of the rectangle is from -3 to -8 on the y-axis. How far is it from -3 to -8?
|dw:1439512117708:dw|
The rectangle is 4 by 5, so the area fo the rectangle is A5 = 4 * 5 = 20
Now let's look at triangle 1. |dw:1439512204247:dw|
A1 = bh/2 = 2 * 2 / 2 = 2
A2 = bh/2 = 4 * 2/2 = 4 |dw:1439512246036:dw|
ok
is that all
We still need triangles 3 and 4.
|dw:1439512375180:dw|
A3 = bh/2 = 4 * 2/2 = 4 A4 = bh/2 = 8 * 2/2 = 8
is the are 20
Now that we have all the small areas, we can find the total area. A = A1 + A2 + A3 + A4 + A5 = 2 + 4 +4 + 8 + 20
Just the rectangle in the middle is 20. The total area is the area of the rectangle plus the area of the 4 triangles. Just add up all the numbers above.
so its 20
40
Wait. i just noticed a mistake I made. All the triangles are correct, but I didn't use the correct length for the rectangle. The rectangle is 6 by 4, so its area is A = LW = 6 * 4 = 24 The total area is A = 2 + 4 +4 + 8 + 24 A = 42

Not the answer you are looking for?

Search for more explanations.

Ask your own question