anonymous one year ago Guys I give medals help me find the y' of y=cos(x+y)

1. anonymous

chain rule again for this one, in the guess of "implicit diff"

2. anonymous

think of it as $f(x)=\cos(x+f(x))$

3. anonymous

then via the chain rule you get $f'(x)=-\sin(x+f(x))\times \left(1+f'(x)\right)$ solve this equation for $$f'(x)$$

4. anonymous

of course it is easier to write $y'=-\sin(x+y)(1+y')$ and solve for $$y'$$

5. anonymous

yeah, can I divide the y'+1 from one side to the other?

6. anonymous

ok I got it

7. anonymous

i will leave the algebra to you , but no, that is not how you solve you need to distribute first

8. anonymous

I got |dw:1439515086039:dw|

9. anonymous

i just remembered my algebra stuff.. thank you again

10. anonymous

looks good to me

11. anonymous

yeah just because you are taking calc doesn't mean the algebra has changed any if my experience algebra is the biggest pitfall, not the ideas of calculus