A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Guys I give medals help me
find the y' of y=cos(x+y)
anonymous
 one year ago
Guys I give medals help me find the y' of y=cos(x+y)

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0chain rule again for this one, in the guess of "implicit diff"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0think of it as \[f(x)=\cos(x+f(x))\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then via the chain rule you get \[f'(x)=\sin(x+f(x))\times \left(1+f'(x)\right)\] solve this equation for \(f'(x)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0of course it is easier to write \[y'=\sin(x+y)(1+y')\] and solve for \(y'\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, can I divide the y'+1 from one side to the other?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will leave the algebra to you , but no, that is not how you solve you need to distribute first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got dw:1439515086039:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just remembered my algebra stuff.. thank you again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah just because you are taking calc doesn't mean the algebra has changed any if my experience algebra is the biggest pitfall, not the ideas of calculus
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.