## anonymous one year ago Which inequality matches the graph? **picture in comments

1. anonymous

2. anonymous

3. anonymous

@satellite73 @Hero @Luigi0210

4. UsukiDoll

hint: we have a solid line so we need the inequality to have $\geq$ or $\leq$ another hint: let (0,0) be a test point. plug in x =0 and y = 0 to see if it works. By the looks of the graph, it seems that the test is gonna fail because (0,0) isn't shaded. find that false case!

5. anonymous

If you realize, the straight line cross with y-axis at (aprox) (0 , 3.5) and with the x-axis at (aprox) (-2.5 , 0), and the formula of the slope is $m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }$ replacing we get $\frac{ 3.5 - 0 }{ 0 - -2.5 }=\frac{ 3.5 }{ 2.5 }=\frac{ 7 }{ 5 }$ and with the formula of point-slope $y-y _{1}=m(x-x _{1})$ replacing we get $y-3.5=\frac{ 7 }{ 5 } (x-0)$ which is equal to $y=\frac{ 7 }{ 5 }x+\frac{ 7 }{ 2 }$ but aparently the point isnt (-2.5 , 0) so the best aproximation is the alternative C, im sorry but i cant see the exact point :(

6. UsukiDoll

nice one @Natriumhydrid even I got it as C too... in a different way based on using (0,0) as a test point and see that the graph doesn't have (0,0) shaded it means that plugging in x = 0 and y =0 into one of the inequalities with the greater than sign will produce a false result. Moreover, we have a solid line, so we have to look for an inequality that's false and has the $\geq$ sign. $-3x+2y\geq 7$

7. UsukiDoll