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anonymous

  • one year ago

Which inequality matches the graph? **picture in comments

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    @satellite73 @Hero @Luigi0210

  4. UsukiDoll
    • one year ago
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    hint: we have a solid line so we need the inequality to have \[\geq \] or \[\leq \] another hint: let (0,0) be a test point. plug in x =0 and y = 0 to see if it works. By the looks of the graph, it seems that the test is gonna fail because (0,0) isn't shaded. find that false case!

  5. anonymous
    • one year ago
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    If you realize, the straight line cross with y-axis at (aprox) (0 , 3.5) and with the x-axis at (aprox) (-2.5 , 0), and the formula of the slope is \[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\] replacing we get \[\frac{ 3.5 - 0 }{ 0 - -2.5 }=\frac{ 3.5 }{ 2.5 }=\frac{ 7 }{ 5 }\] and with the formula of point-slope \[y-y _{1}=m(x-x _{1})\] replacing we get \[y-3.5=\frac{ 7 }{ 5 } (x-0)\] which is equal to \[y=\frac{ 7 }{ 5 }x+\frac{ 7 }{ 2 }\] but aparently the point isnt (-2.5 , 0) so the best aproximation is the alternative C, im sorry but i cant see the exact point :(

  6. UsukiDoll
    • one year ago
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    nice one @Natriumhydrid even I got it as C too... in a different way based on using (0,0) as a test point and see that the graph doesn't have (0,0) shaded it means that plugging in x = 0 and y =0 into one of the inequalities with the greater than sign will produce a false result. Moreover, we have a solid line, so we have to look for an inequality that's false and has the \[\geq \] sign. \[-3x+2y\geq 7\]

  7. UsukiDoll
    • one year ago
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