A line passes through the point −6, 1 and has a slope of 4 over 3.
Write an equation in slope-intercept form for this line.

- teller

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- anonymous

does "4 over 3" mean \(\frac{4}{3}\)?

- teller

Yes..

- anonymous

ok use
\[y-y_1=m(x-x_1)\] with \[x_1=-6,y_1=1,m=\frac{4}{3}\]

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## More answers

- teller

Confused... But I will try it
6-1^1= 4/3(x-x^1) ??

- misty1212

HI!!

- misty1212

i see you are a bit confused

- misty1212

you do know that the answer you are supposed to get has an \(x\) and a \(y\) in it right?

- teller

Yes I'm confused and no .That's why I'm asking for help .

- misty1212

it should look like \(y=mx+b\) for some \(m\) and \(b\)

- misty1212

the \(x\) and \(y\) are variables in this expression \[y-y_1=m(x-x_1)\] they are the \(x\) and \(y\) in the answer
the \(m\) and \(x_1,y_1\) are numbers
@satellite73 showed you what those numbers are

- teller

So y-1=4/3(x-(-6)

- misty1212

that looks good

- misty1212

\[y-1=\frac{4}{3}(x+6)\] looks even better since \(-(-6)=+6\)

- misty1212

you are not done yet though, you still have to solve for \(y\) which takes exactly two steps

- teller

So how do I do that?

- misty1212

a) distribute the \(\frac{4}{3}\) on the right
b) add \(1\) to both sides

- misty1212

does that make any sense to you?

- teller

y=4/3x+9??

- misty1212

yes!

- misty1212

\[\color\magenta\heartsuit\]

- teller

Mind if you help me with another one?

- misty1212

sure
and say hi to penn for me

- teller

Hello penn?.?.Don't know who that is lol but Hi...
A line passes through the point -2, -4 and has a slope of −7
.
Write an equation in slope-intercept form for this line.

- anonymous

this one is even easier because there is no fraction

- anonymous

same as before \[y+4=-7(x+2)\]

- misty1212

what @satellite73 said, then you have to solve for \(y\) using the same two steps
a) distribute on the right
b) subtract 4 from both sides

- teller

y=-7x-18??

- misty1212

https://www.youtube.com/watch?v=oJhYySXzOq0

- misty1212

yeah looks good

- teller

A line passes through the point 7, 5 and has a slope of 2
.
Write an equation in slope-intercept form for this line.
Would it look like this ?
y+5=2(x+7)

- misty1212

not quite

- misty1212

the reason they were plus before was because each number was negative
but the formula is
\[y-y_1=m(x-x_1)\]

- misty1212

so change those plus signs to minus signs

- teller

so each time it's a plus it will be a minus and when ever it's a minus it will be a plus?

- misty1212

yes

- teller

so y-5=2(x+7) or is y-5=2(x-7)

- misty1212

second one

- teller

so y=2x-9?

- misty1212

looks good

- teller

A line passes through the point
−8, 7 and has a slope of 5/4
.
Write an equation in slope-intercept form for this line.
y+7=5/4(x+8)

- misty1212

not quite
there is one mistake in a sign
do you see it?

- teller

would it be (x-8)??

- misty1212

no that part is right

- teller

so -7??

- misty1212

yes

- teller

so y-7=5/4(x+8)

- misty1212

at the risk of repeating myself, it is \[\huge y-y_1=m(x-x_1)\] the minus signs are in the formula

- misty1212

yeah that is right

- teller

y=5/4x+17??

- misty1212

yup

- teller

it said it was incorrect...

- teller

it was minus 17..

- misty1212

no it isn't

- teller

That's what the problem said and when i hit explain it gave me the answer...

- misty1212

\[y-7=\frac{5}{4}(x+8)\\
y=7=\frac{5}{4}x+10\\
y=\frac{5}{4}x+17\]

- teller

sometimes i think the thing is rigged
...

- misty1212

was the point\((7,-8)\)?

- teller

no -8,7

- misty1212

yeah sorry that is what i meant

- misty1212

if the point is \((-8,7)\) then it should be \(y=\frac{5}{4}x+17\)

- misty1212

tell them it is a mistake

- teller

A line passes through the point
−6, -1and has a slope of −5/2
.
Write an equation in slope-intercept form for this line.
Would it be y+1=-5/2(x+6)

- misty1212

yes

- teller

so it would be y=-5/2x-16??

- misty1212

hmm lets check

- misty1212

\[y+1=-\frac{5}{2}(x+6)\]\[y+1=-\frac{5}{2}x-15\]\[y=-\frac{5}{2}x-16\]

- teller

A line passes through the point 6, 1 and has a slope of 2.
Write an equation in slope-intercept form for this line.
so y-1=2(x-6)??
y=2x-11??

- misty1212

yes

- teller

One more problem then I will be done with that subject.I greatly appreciate you for helping me !
A line passes through the point
4, -9 and has a slope of −4
.Write an equation in slope-intercept form for this line.
y+9=-4(x-4) or is it y+9=-4(x+4)

- misty1212

fist one

- misty1212

first

- teller

so the final answer would be y=-4x+7

- misty1212

yes

- misty1212

you done with them all?

- teller

said I was incorrect...

- misty1212

ok lets check

- misty1212

A line passes through the point
(4, -9) and has a slope of −4 right?

- misty1212

\[y+9=-4(x-4)\\
y+9=-4x+16\\
y=-4x+7\]

- misty1212

it is right, if that was the question

- teller

We are given that the line passes through the point
−4, 9
.
So, the equation must be true when
=x4
and
=y−9
.
=−9+−44b
We can solve this equation for the
y
-intercept
b
.
−9
=+−44b
−9
=+−16b
7
=b
We now write the equation of the line in slope-intercept form.
=y+−4x7
Here is the answer.
=y+−4x7

- teller

that's what it said

- teller

but thank you for the help..

- misty1212

i have read that twice now and it does not make any sense to me

- misty1212

what does
=y+−4x7 even mean?

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