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anonymous
 one year ago
Please help me, I don't know where I went wrong and I keep getting this same answer! *WILL FAN AND MEDAL*! Please help me check my answer, PLEASE!
anonymous
 one year ago
Please help me, I don't know where I went wrong and I keep getting this same answer! *WILL FAN AND MEDAL*! Please help me check my answer, PLEASE!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the standard form of the equation of the parabola with a focus at (4, 0) and a directrix at x = 4. A. y^2 = 8x B. 16y = x^2 C. y = 1/16x^2 D. x = 1/16y^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I keep getting y^2 = 1/16x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@misty1212 @satellite73 @Peaches15 anybody??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do you know? @kali_sky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We know that the directrix is x=4 so the equation must be y^2, and we know that the focus is (4,0) so the center of the parabola is (0,0) and p=4, then using the formula \[\Large (yk)^{2}=4p(xh)\] of the parabola with center (h,k) and p=semiaxis length, replacing we get \[\Large(y0)^{2}=4\times4(x0)\] \[\Large y ^{2}=16x\]
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