help plz

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Explain the difference between using the sine ratio to solve for a missing angle in a right triangle versus using the cosecant ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.
@surjithayer can you help me plz

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Explain the difference between using the sine ratio to solve for a missing angle in a right triangle versus using the cosecant ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.
HI!!
one is the reciprocal of the other
hi can you help me plz
but if you are looking for an angle, you really have to use sine lets give an example
|dw:1439518386921:dw| suppose we are looking for angle \(x\)
it asking the dfference
ok
then you have \[\sin(x)=\frac{5}{7}\] and you also have \[\csc(x)=\frac{7}{5}\]
but you want the angle, so you have to use the inverse trig function to find it
yess
\[\sin(x)=\frac{5}{7}\\ \sin^{-1}(\frac{5}{7})=x\] you would use a calculator to get than number
but no calculator has an inverse cosecant on it,so you would not be able to find \[\csc^{-1}(\frac{7}{5})\] so get \(x\)
you would have to use the inverse sine (sometimes called the "arcsine") that is the only way you could do it
okay so the difference is that sine you can use inverse and cse u can't
yes
thanks
\[\color\magenta\heartsuit\]

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