MEDAL AND FAN!!!!

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MEDAL AND FAN!!!!

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Other answers:

i have one more also
|dw:1439522907558:dw| same thing as before in simplest form
if u can my time is almost up i need them quickly i am very sorry..
\[\Large (27a^{-3})^{-\frac{ 2 }{ 3}}=\left( \displaystyle\frac{27}{a ^{3}} \right)^{\frac{ -2 }{ 3 }}=\left( \displaystyle\frac{3^{3}}{a ^{3}} \right) ^{\frac{ -2 }{ 3 }}=\left( \displaystyle\frac{3}{a} \right)^{3\times \frac{ (-2) }{ 3 }}=\left( \displaystyle\frac{3}{a} \right)^{-2}\] \[\Large=\left( \displaystyle\frac{a}{3} \right)^{2}=\frac{ a ^{2} }{ 9 }\]
is that last fraction the first answer?
yea
what about my second question? does anybody know im sorry for being rude
|dw:1439523204380:dw| this is it again
\[\Large (8a ^{-6})^{-\frac{ 2 }{ 3 }}=(2^{3} (a ^{-2})^{3})^{\frac{ -2 }{ 3 }}=(2a ^{-2})^{-2}=\frac{ a ^{4} }{ 4 }=\frac{ a ^{4} }{ 2^{2} }=\left( \displaystyle\frac{a ^{2}}{2} \right)^{2}\]
i cant see the full thing can u tell me the answer sorry
my time has 2mins
\[\Large \frac{ a ^{4} }{ 4 }=\left( \displaystyle\frac{a ^{2}}{2} \right) ^{2}\]
thank you soo much
i passed thank you @Natriumhydrid !!!!!!!!!!
yw bro

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