anonymous
  • anonymous
MEDAL AND FAN!!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@LynFran
anonymous
  • anonymous
write in simplest form
anonymous
  • anonymous
|dw:1439522709480:dw|

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More answers

anonymous
  • anonymous
i have one more also
anonymous
  • anonymous
|dw:1439522907558:dw| same thing as before in simplest form
anonymous
  • anonymous
if u can my time is almost up i need them quickly i am very sorry..
anonymous
  • anonymous
\[\Large (27a^{-3})^{-\frac{ 2 }{ 3}}=\left( \displaystyle\frac{27}{a ^{3}} \right)^{\frac{ -2 }{ 3 }}=\left( \displaystyle\frac{3^{3}}{a ^{3}} \right) ^{\frac{ -2 }{ 3 }}=\left( \displaystyle\frac{3}{a} \right)^{3\times \frac{ (-2) }{ 3 }}=\left( \displaystyle\frac{3}{a} \right)^{-2}\] \[\Large=\left( \displaystyle\frac{a}{3} \right)^{2}=\frac{ a ^{2} }{ 9 }\]
anonymous
  • anonymous
is that last fraction the first answer?
anonymous
  • anonymous
yea
anonymous
  • anonymous
what about my second question? does anybody know im sorry for being rude
anonymous
  • anonymous
|dw:1439523204380:dw| this is it again
anonymous
  • anonymous
\[\Large (8a ^{-6})^{-\frac{ 2 }{ 3 }}=(2^{3} (a ^{-2})^{3})^{\frac{ -2 }{ 3 }}=(2a ^{-2})^{-2}=\frac{ a ^{4} }{ 4 }=\frac{ a ^{4} }{ 2^{2} }=\left( \displaystyle\frac{a ^{2}}{2} \right)^{2}\]
anonymous
  • anonymous
i cant see the full thing can u tell me the answer sorry
anonymous
  • anonymous
my time has 2mins
anonymous
  • anonymous
\[\Large \frac{ a ^{4} }{ 4 }=\left( \displaystyle\frac{a ^{2}}{2} \right) ^{2}\]
anonymous
  • anonymous
thank you soo much
anonymous
  • anonymous
i passed thank you @Natriumhydrid !!!!!!!!!!
anonymous
  • anonymous
yw bro

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