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anonymous

  • one year ago

MEDAL AND FAN!!!!

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  1. anonymous
    • one year ago
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    @LynFran

  2. anonymous
    • one year ago
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    write in simplest form

  3. anonymous
    • one year ago
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    |dw:1439522709480:dw|

  4. anonymous
    • one year ago
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    i have one more also

  5. anonymous
    • one year ago
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    |dw:1439522907558:dw| same thing as before in simplest form

  6. anonymous
    • one year ago
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    if u can my time is almost up i need them quickly i am very sorry..

  7. anonymous
    • one year ago
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    \[\Large (27a^{-3})^{-\frac{ 2 }{ 3}}=\left( \displaystyle\frac{27}{a ^{3}} \right)^{\frac{ -2 }{ 3 }}=\left( \displaystyle\frac{3^{3}}{a ^{3}} \right) ^{\frac{ -2 }{ 3 }}=\left( \displaystyle\frac{3}{a} \right)^{3\times \frac{ (-2) }{ 3 }}=\left( \displaystyle\frac{3}{a} \right)^{-2}\] \[\Large=\left( \displaystyle\frac{a}{3} \right)^{2}=\frac{ a ^{2} }{ 9 }\]

  8. anonymous
    • one year ago
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    is that last fraction the first answer?

  9. anonymous
    • one year ago
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    yea

  10. anonymous
    • one year ago
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    what about my second question? does anybody know im sorry for being rude

  11. anonymous
    • one year ago
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    |dw:1439523204380:dw| this is it again

  12. anonymous
    • one year ago
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    \[\Large (8a ^{-6})^{-\frac{ 2 }{ 3 }}=(2^{3} (a ^{-2})^{3})^{\frac{ -2 }{ 3 }}=(2a ^{-2})^{-2}=\frac{ a ^{4} }{ 4 }=\frac{ a ^{4} }{ 2^{2} }=\left( \displaystyle\frac{a ^{2}}{2} \right)^{2}\]

  13. anonymous
    • one year ago
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    i cant see the full thing can u tell me the answer sorry

  14. anonymous
    • one year ago
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    my time has 2mins

  15. anonymous
    • one year ago
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    \[\Large \frac{ a ^{4} }{ 4 }=\left( \displaystyle\frac{a ^{2}}{2} \right) ^{2}\]

  16. anonymous
    • one year ago
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    thank you soo much

  17. anonymous
    • one year ago
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    i passed thank you @Natriumhydrid !!!!!!!!!!

  18. anonymous
    • one year ago
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    yw bro

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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