## anonymous one year ago Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work. Part B: The area of a rectangle is (81x2 − 4y2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work.

1. anonymous

Part A By the identity $\Large (a ^{2} \pm 2ab+b ^{2})=(a \pm b)^{2}$ $\Large(16x^2 − 8x + 1)=(4x-1)^{2}$ so the side of the square is 4x-1 Part B By the identity $\Large(a ^{2} - b ^{2})=(a-b)(a+b)$ $\Large(81x^2 − 4y^2)=(9x-2y)(9x+2y)$ then the sides of the rectangle are 9x-2y and 9x+2y

2. jtvatsim

Does that help @SOAD_Fan ? :)

3. anonymous

Ja :)

4. jtvatsim

Awesome! Just wanted to make sure. @Natriumhydrid did a good job. :)