anonymous
  • anonymous
Let (7,-5) be a point on the terminal side of theta. Find the exact values of sin, csc, and cot.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Nnesha
  • Nnesha
(x,y) x = cos y= sin so in which quadrant you should draw the right triangle ?
Nnesha
  • Nnesha
|dw:1439523692837:dw|
Nnesha
  • Nnesha
remember that \[\huge\color{green}{\textrm CAST!}\] rule

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so I quadrant?
Nnesha
  • Nnesha
given point is (7,-5) what is cos and what is sin ?
Nnesha
  • Nnesha
like i said x-coordinate represents cos and y-coordinate = sin
anonymous
  • anonymous
sin is -5 cos is 7?
Nnesha
  • Nnesha
yes right so in which quadrant sin is negative but cos is POSITIVE !
anonymous
  • anonymous
so quadrant IV
Nnesha
  • Nnesha
yes right |dw:1439524044821:dw| apply the Pythagorean theorem to find 3rd side of right triangle
Nnesha
  • Nnesha
a^2+b^2=c^2 c=hypotenuse
anonymous
  • anonymous
√74
Nnesha
  • Nnesha
right you need to know these definition of sin, cos , and tan \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] |dw:1439524382597:dw| so sin = ??
anonymous
  • anonymous
so -5/√74
Nnesha
  • Nnesha
yes right but you can't leave the radical sign at the denominator so multiply denominator and numerator by sqrt{74}
Nnesha
  • Nnesha
\[\huge\rm \frac{ -5 }{ \sqrt{74} } \times \frac{ \sqrt{74} }{ \sqrt{74} }\]
anonymous
  • anonymous
I think I did something wrong but I got -5
Nnesha
  • Nnesha
no that's not correct solve taht
Nnesha
  • Nnesha
\[\huge\rm \frac{ -5 }{ \sqrt{74} } \times \frac{ \sqrt{74} }{ \sqrt{74} }\] what did you get ?
anonymous
  • anonymous
-.58?
Nnesha
  • Nnesha
well keep it in fraction form
Nnesha
  • Nnesha
*exact values*
anonymous
  • anonymous
so -43.0/74?
Nnesha
  • Nnesha
\[\huge\rm \frac{ -5 }{ \sqrt{74} } \times \frac{ \sqrt{74} }{ \sqrt{74} }\] now we don't need decimal answer \[\frac{ -5\sqrt{74} }{ 74 }\]
Nnesha
  • Nnesha
^^that is sin
Nnesha
  • Nnesha
now find csc remember sec, csc , cot are reciprocal of cos , sin , tan
anonymous
  • anonymous
ohhh that looks so much better
anonymous
  • anonymous
so csc is h/a?
Nnesha
  • Nnesha
sin and csc are reciprocal of each other if sin = o/h then csc = h/o
anonymous
  • anonymous
oh opps so its √74/5
Nnesha
  • Nnesha
no
Nnesha
  • Nnesha
opposite side equal to what ?
Nnesha
  • Nnesha
|dw:1439525411597:dw| opposite of theta
anonymous
  • anonymous
-5
Nnesha
  • Nnesha
yes so csc = ?
anonymous
  • anonymous
oh did I just forget the -? √74/-5
Nnesha
  • Nnesha
yes right is not *just* :P
anonymous
  • anonymous
haha sorry
Nnesha
  • Nnesha
okay \[\tan = \frac{ \sin }{ \cos } ~so ~\cot =\frac{ \cos }{ \sin }\]
anonymous
  • anonymous
7/-5?
Nnesha
  • Nnesha
perfect!
anonymous
  • anonymous
you are the best! thank you so much!
Nnesha
  • Nnesha
my pleasure.

Looking for something else?

Not the answer you are looking for? Search for more explanations.