Republican31
  • Republican31
Tell whether the following is a function. If not explain why. {(-3, 5), (0, 7), (0, 6), (4, 1)}. It's not a function, right? I don't see any possible pattern.
Mathematics
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Republican31
  • Republican31
Tell whether the following is a function. If not explain why. {(-3, 5), (0, 7), (0, 6), (4, 1)}. It's not a function, right? I don't see any possible pattern.
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Nnesha
  • Nnesha
if x values repeats then relation is not a function
Nnesha
  • Nnesha
and yes right
UsukiDoll
  • UsukiDoll
it's not a function because we have 0 twice in the domain.

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UsukiDoll
  • UsukiDoll
[ -3 0 0 4] uh oh . I see 0 twice... not a function :)
anonymous
  • anonymous
To be a function each x value must have a unique y value, so it isnt a function because x=0 has 2 y-values
Republican31
  • Republican31
Alright thank you! I didn't think that it was, and I forgot the rule about x values not being repeated. And it's getting late and I've been doing math all day, excuses excuses... Thank you @UsukiDoll for putting it into terms that will work in the assignment also. Just curious I want to make sure, it doesn't matter if y values repeat, right?
Nnesha
  • Nnesha
no just ignore the y values
UsukiDoll
  • UsukiDoll
the x values matter more if we're given a problem like this.
Republican31
  • Republican31
Alright thank you all!

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