## A community for students. Sign up today

Here's the question you clicked on:

## JayDelV one year ago PROBABILITY AND STATISTICS (WILL AWARD A MEDAL AND FAN ) A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?

• This Question is Closed
1. JayDelV

I need to be walked through the steps, I'm not very good at word problems.

2. anonymous

There are two events (foul shots), A and B. The probability of A then B is$P (A\text{ then } B) = P(A) \times P(B)$Don't forget, the probabilities need to be expressed as decimals before doing any calculations with them.

3. JayDelV

So using that equation I would get my answer?

4. JayDelV

@ospreytriple

5. anonymous

Yes. Show me what you get.

6. JayDelV

I'm not sure what to plug in to what

7. anonymous

Event A is missing the first foul shot. What's P(A)?

8. JayDelV

40?

9. anonymous

Express as a decimal.

10. JayDelV

.40

11. JayDelV

?

12. anonymous

Right. Event B is missing the second foul shot. What's P(B) expressed as a decimal?

13. JayDelV

.05

14. anonymous

Right. So the event of Event A happening then Event B happening is P(A) x P(B). What do you get. Express your final answer as a percent.

15. JayDelV

I'm not sure if i'm right, but 2 percent?

16. anonymous

Correct. Well done! It's a small percentage because, even if the first shot is missed, the second shot is almost never missed. Make sense?

17. JayDelV

Yes! Thank you. Do you mind helping me with another one? If not that'll be fine.

18. anonymous

OK. Delete this question and post your other one.

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy