If g(x) = x2 – 2x, find the value of g(-3) + 1.
Is 8 = 4 + 4 correct?

- Republican31

If g(x) = x2 – 2x, find the value of g(-3) + 1.
Is 8 = 4 + 4 correct?

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

If you mean
\[\Large g(x)=x^2-2x\]
then
\[\Large g(-3)+1=(-3)^{2}-2(-3)+1=9+6+1=16\]

- Republican31

Yes sorry that is what I meant. I didn't notice that little formatting error.

- Republican31

But it's -3 + 1, meaning -2, right?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Jhannybean

Yep

- Republican31

So does that mean it is 8 or 16?

- Jhannybean

Wait a minute.

- anonymous

If you mean
\[g(-3+1)\] then is 8, but if is
\[g(-3)+1\] then is 16

- Republican31

Ugh...

- Jhannybean

\[g(\color{red}{-3})+1=(\color{red}{-3})^{2}-2(\color{red}{-3})+1=\color{red}{9}+6+1=16\]

- Jhannybean

Which part is confusing you exactly?

- Republican31

So 16 = 9+6+1 is correct?

- Jhannybean

Well, when you add 9 + 6 + 1, what do you get?

- Republican31

I just don't understand how (-3) + 1 is any different from (-3 + 1) unless it's because of the g in front. I don't like these functions.

- Jhannybean

Well, think about \(x=-3\) , does that also mean \(x=-3+1\)?

- Jhannybean

Your question is basically saying that you have a function \(g(x) = x^2-2x\), now when \(x=-3\) you replace \(-3\) wherever you see \(x\) in the function.

- Republican31

N...No?

- Republican31

Okay. And then the +1? I see it come in at -2x, but not for the x^2.

- Jhannybean

Ontop of that, you're adding a `+1` to your function's value, therefore \(g(x)+1\) is what you're solving for.

- Jhannybean

Do you see it now?

- anonymous

the +1 you can add up at the end

- Republican31

Okay but why isn't it + 2 for both times that x was used?

- Jhannybean

+2?

- Jhannybean

Okay let's try a different question. Like to try a different one? This time you will solve it.

- Republican31

I'm sorry I just am having trouble understanding. What I'm wondering is if there was
x2 - 2x, then doesn't that mean (-3) + 1 was used twice, so there should be a + 1 from each time x was used in the equation

- Republican31

Alright.

- Jhannybean

Let's take \(f(x) = x^3+3x+5\) and we're finding \(f(-5)+3\)

- Republican31

Okay.

- Jhannybean

So what is the first step you would do?

- Republican31

= 125 - 15 + 5?

- Jhannybean

Let's check

- Republican31

Sorry -125

- Jhannybean

\[f(\color{blue}{-5}) = (\color{blue}{-5})^3 +3(\color{blue}{-5})+5\]

- Jhannybean

Did you get -125 - 15 + 5?

- Republican31

Ya. I saw my mistake of having 125 instead of -125.

- Jhannybean

Alright :D and that gives you -135 correct?

- Republican31

yes

- Jhannybean

Now that we've solved that portion, we're going to add \(+3\) to our answer. This is because we are looking for \(f(-5)\color{blue}{+3}\) and not just \(f(-5)\)

- Jhannybean

So then what is -135 + 3?

- Republican31

Alright but I just was wondering why it isn't (-5) + 3^2. And it's 132.

- Republican31

*-132

- Jhannybean

To my knowledge, we're changing and shifting a function by changing the x value. you `might` be over thinking it!

- Republican31

Alright. Thank you so much for all your help!

Looking for something else?

Not the answer you are looking for? Search for more explanations.