Republican31
  • Republican31
If g(x) = x2 – 2x, find the value of g(-3) + 1. Is 8 = 4 + 4 correct?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
If you mean \[\Large g(x)=x^2-2x\] then \[\Large g(-3)+1=(-3)^{2}-2(-3)+1=9+6+1=16\]
Republican31
  • Republican31
Yes sorry that is what I meant. I didn't notice that little formatting error.
Republican31
  • Republican31
But it's -3 + 1, meaning -2, right?

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Jhannybean
  • Jhannybean
Yep
Republican31
  • Republican31
So does that mean it is 8 or 16?
Jhannybean
  • Jhannybean
Wait a minute.
anonymous
  • anonymous
If you mean \[g(-3+1)\] then is 8, but if is \[g(-3)+1\] then is 16
Republican31
  • Republican31
Ugh...
Jhannybean
  • Jhannybean
\[g(\color{red}{-3})+1=(\color{red}{-3})^{2}-2(\color{red}{-3})+1=\color{red}{9}+6+1=16\]
Jhannybean
  • Jhannybean
Which part is confusing you exactly?
Republican31
  • Republican31
So 16 = 9+6+1 is correct?
Jhannybean
  • Jhannybean
Well, when you add 9 + 6 + 1, what do you get?
Republican31
  • Republican31
I just don't understand how (-3) + 1 is any different from (-3 + 1) unless it's because of the g in front. I don't like these functions.
Jhannybean
  • Jhannybean
Well, think about \(x=-3\) , does that also mean \(x=-3+1\)?
Jhannybean
  • Jhannybean
Your question is basically saying that you have a function \(g(x) = x^2-2x\), now when \(x=-3\) you replace \(-3\) wherever you see \(x\) in the function.
Republican31
  • Republican31
N...No?
Republican31
  • Republican31
Okay. And then the +1? I see it come in at -2x, but not for the x^2.
Jhannybean
  • Jhannybean
Ontop of that, you're adding a `+1` to your function's value, therefore \(g(x)+1\) is what you're solving for.
Jhannybean
  • Jhannybean
Do you see it now?
anonymous
  • anonymous
the +1 you can add up at the end
Republican31
  • Republican31
Okay but why isn't it + 2 for both times that x was used?
Jhannybean
  • Jhannybean
+2?
Jhannybean
  • Jhannybean
Okay let's try a different question. Like to try a different one? This time you will solve it.
Republican31
  • Republican31
I'm sorry I just am having trouble understanding. What I'm wondering is if there was x2 - 2x, then doesn't that mean (-3) + 1 was used twice, so there should be a + 1 from each time x was used in the equation
Republican31
  • Republican31
Alright.
Jhannybean
  • Jhannybean
Let's take \(f(x) = x^3+3x+5\) and we're finding \(f(-5)+3\)
Republican31
  • Republican31
Okay.
Jhannybean
  • Jhannybean
So what is the first step you would do?
Republican31
  • Republican31
= 125 - 15 + 5?
Jhannybean
  • Jhannybean
Let's check
Republican31
  • Republican31
Sorry -125
Jhannybean
  • Jhannybean
\[f(\color{blue}{-5}) = (\color{blue}{-5})^3 +3(\color{blue}{-5})+5\]
Jhannybean
  • Jhannybean
Did you get -125 - 15 + 5?
Republican31
  • Republican31
Ya. I saw my mistake of having 125 instead of -125.
Jhannybean
  • Jhannybean
Alright :D and that gives you -135 correct?
Republican31
  • Republican31
yes
Jhannybean
  • Jhannybean
Now that we've solved that portion, we're going to add \(+3\) to our answer. This is because we are looking for \(f(-5)\color{blue}{+3}\) and not just \(f(-5)\)
Jhannybean
  • Jhannybean
So then what is -135 + 3?
Republican31
  • Republican31
Alright but I just was wondering why it isn't (-5) + 3^2. And it's 132.
Republican31
  • Republican31
*-132
Jhannybean
  • Jhannybean
To my knowledge, we're changing and shifting a function by changing the x value. you `might` be over thinking it!
Republican31
  • Republican31
Alright. Thank you so much for all your help!

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