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anonymous

  • one year ago

Convert the following polar representation of this complex number into it's regular form: z=4(cos pi/2+isinpi/2)? A.(0,4) B.(-4,0) C.(4sqrt2,0) D.(0,-4)

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  1. jtvatsim
    • one year ago
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    The question seems a bit strange as currently worded... The answer choices don't match up... since the complex number is ALREADY in polar representation... :)

  2. anonymous
    • one year ago
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    ill double check the question

  3. anonymous
    • one year ago
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    @jtvatsim fixed it:)

  4. jtvatsim
    • one year ago
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    That makes more sense... but now let's see if I can figure out the real question. :P lol

  5. jtvatsim
    • one year ago
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    Alright, so for these you need to either have memorized what cos(pi/2) and sin(pi/2) are, use a calculator (in radians mode), or use the unit circle. :)

  6. jtvatsim
    • one year ago
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    I happen to see these a lot, so I can tell you that cos(pi/2) = 0 and sin(pi/2) = 1.

  7. jtvatsim
    • one year ago
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    OK so far?

  8. anonymous
    • one year ago
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    yeah

  9. jtvatsim
    • one year ago
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    Alright, so now we just simplify the given number: z = 4(cos pi/2 + i sin pi/2) = 4(0 + i * 1) = 4( i ) = 4i.

  10. jtvatsim
    • one year ago
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    If you are feeling really "textbook mathy" this is the same as 4i = 0 + 4i or some people write it like a coordinate (0, 4) where it is understood that the first coordinate gives the "real" number values, and the second coordinate gives the "imaginary" i values.

  11. anonymous
    • one year ago
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    so in order to get the answer that's all you do?

  12. jtvatsim
    • one year ago
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    Yes, converting from polar form to regular form is much easier than going the other direction.

  13. anonymous
    • one year ago
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    Thanks:) So the final amswer is A. (0,4

  14. jtvatsim
    • one year ago
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    No problem! You are good to go!

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