## anonymous one year ago Fan and medal for easy problem check below :) Solve the following system of equations. -3x + 4y = 80 x + 4y = 32 A. x = 2, y = 21.5 B. x = 11, y = -12 C. x = 8, y = 6 D. x = -12, y = 11

i got this hold up

2. anonymous

$-3x+4y=80, x+4y=32$ multiplying the second equation by (-1) we get $-3x+4y=80, -x-4y=-32$ now, we sum both equations getting $-4x=48 \rightarrow x=-12$ and replacing x=-12 in the first equation we get $-3(-12)+4y=80 \rightarrow 36+4y=80 \rightarrow 4y=44 \rightarrow y=11$ so x=-12 and y=11 is the solution to the system of equations