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anonymous
 one year ago
Precalc help? Check my answer?
Find the center, vertices, and foci of the ellipse with equation 3x^2 + 6y^2 = 18
A. Center: (0, 0); Vertices: (0,sqrt6),(0,sqrt6); Foci: (0,sqrt3),(0,sqrt3)
B. Center: (0, 0); Vertices: (sqrt6,0),(sqrt6,0); Foci: (sqrt3,0),(sqrt3,0)
C. Center: (0, 0); Vertices: (6, 0), (6, 0); Foci: (3*sqrt3,0),(3*sqrt3,0)
D. Center: (0, 0); Vertices: (0, 6), (0, 6); Foci: (0,3*sqrt3),(0,3*sqrt3)
I got A as my answer. Am I correct?
anonymous
 one year ago
Precalc help? Check my answer? Find the center, vertices, and foci of the ellipse with equation 3x^2 + 6y^2 = 18 A. Center: (0, 0); Vertices: (0,sqrt6),(0,sqrt6); Foci: (0,sqrt3),(0,sqrt3) B. Center: (0, 0); Vertices: (sqrt6,0),(sqrt6,0); Foci: (sqrt3,0),(sqrt3,0) C. Center: (0, 0); Vertices: (6, 0), (6, 0); Foci: (3*sqrt3,0),(3*sqrt3,0) D. Center: (0, 0); Vertices: (0, 6), (0, 6); Foci: (0,3*sqrt3),(0,3*sqrt3) I got A as my answer. Am I correct?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.03x^2 + 6y^2 = 18 \[\frac{ 3x^2 }{ 18 }+\frac{ 6y^2 }{ 18 }=1\]\[\frac{ x^2 }{ 6 }+\frac{ y^2 }{ 3 }=1\] so center is (0,0) \[a=\sqrt{6}\]\[b=\sqrt{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, alright. Thank you very much for your help!
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