A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
4√(80x^17w^8)
anonymous
 one year ago
4√(80x^17w^8)

This Question is Closed

CoconutJJ
 one year ago
Best ResponseYou've already chosen the best response.04 times sqrt of 4th root ?

CoconutJJ
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439531008723:dw

CoconutJJ
 one year ago
Best ResponseYou've already chosen the best response.0i c.... Assuming you're suppose to simplify, do you remember the exponent laws that apply to radicals

CoconutJJ
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439531324193:dw

CoconutJJ
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439531372578:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so divide x^17 by 4? like 17/4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would i put it in a decimal form?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Here's an alternative way to think through these types of questions. First, think about the normal square roots. When you have square roots you need two factors inside in order to "escape" as in \[\sqrt{x^2} = \sqrt{x \cdot x} = x\] but if we only have one factor we are "trapped" \[\sqrt{2} = stuck\] Does that make sense so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 2x^4w^4 4th√(5x^13 w^2) @jtvatsim

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1k let me check what you did. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1You are close, just a few minor errors, but overall it seems like you have the idea. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you tell me which part i got wrong?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Alright, so effectively we want to "bunch" our factors in groups of 4 whenever possible in order to escape the radical. We need groups of 4 because of the 4th root. \[\sqrt[4]{80x^{17}w^8} = \sqrt[4]{5\cdot2^4 \cdot x^4 \cdot x^4 \cdot x^4 \cdot x^4 \cdot x \cdot w^4 \cdot w^4} \] \[= 2\cdot x\cdot x \cdot x \cdot x \cdot w \cdot w\sqrt[4]{5x} = 2x^4w^2\sqrt[4]{5x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh that is much easier

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Does that help you "see" it more clearly? I found that explanation to make the most sense when I was learning. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it helped a lot! thank you so much!

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1You are welcome! This same trick works no matter what root you are dealing with! Bring on the 100th roots, just bunch into groups of 100 (maybe not... don't give your teachers any ideas...) Have a good one! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.