anonymous
  • anonymous
General Chemistry Challenge Problem: Gases Cyanogen, a highly toxic gas is 46.2% C and 53.8% N by mass. At 25 degrees Celsius and 751 torr, 1.05g of cyanogen occupies 0.500 L. A) What is the molecular formula of cyanogen. B) Predict the molecular structure C) Predict its polarity.
Chemistry
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Have the answers. Lets see who knows all 3.
anonymous
  • anonymous
Medal and fan.
aaronq
  • aaronq
a) Formula for \(\sf C_xN_y\) \(\sf PV=nRT=\dfrac{mRT}{M}\) \(\sf M_{C_xN_y}=\dfrac{mRT}{PV}=\dfrac{1.05~g*(62.36367~L~torr~K^{-1}mol^{-1})*298.15~K }{751~torr*0.5~L}=51.99~g/mol \) \(\sf M_{C_xN_y}\approx 52~g/mol=x~12~g/mol+y~14~g/mol\) Trial and error gives \(\sf C_2N_2\) The structure is probably |dw:1439562426305:dw| The structure does not have a permanent dipole moment because of symmetry - individual dipole moments caused by the lone pairs on the N terminal atoms cancel each other out.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

aaronq
  • aaronq
|dw:1439563030483:dw|
anonymous
  • anonymous
Wow, nice. All 3 steps correct.

Looking for something else?

Not the answer you are looking for? Search for more explanations.