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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can someone please help. Im kind of desperate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One can imagine various points at which the line segment can be broken up. in fact, it would form a continuum up to the starting and end points.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Try and think of it like this, a triangle contained in a semicircle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439458637345:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In that instance you could have the top point of the triangle anywhere along the 180 degrees of the semicircle except at 0 and 180 degrees where you would just have a line. so at most you can create 1802 triangles i.e. 178 different triangles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now that is if the points of the triangle are discrete, if they are continuous (i.e. using the real number system, then the number approaches an infinity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, im here... i understand what youre saying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, you can write your answer as follows: For the set of points where the points are from the set of integers , the number of triangles that can be created is 178.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright... but how do i make this a probability?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0simple. there is 1/178 chance when you divide up the line that one of the 178 triangles will be chosen

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH isee thanks so much!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, but that answer seems to be wrong...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im using an online math stimulator where it goves me different problems.... and it says that this answer is wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Addresss of online simulator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its on aops.com but you have to pay to access it...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, @mathlete, @welshfella

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0hmm tricky one this for a triangle to be formed any one side must not be equal or greater than the sum of the other 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I used a semi circle, perhaps use a full circle. count 0 and 180 once for both semicircles only. that means 360  2 or 358.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah what? @Emeyluv99

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, it makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you take a screenshot of the question and post it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH. i got the answer...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i used @welshfella 's idea and made some inequalities and graphed it. the answer was 1/4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which of course isnt 1/4!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres another question i needed help on... do you think you could try to help again please?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks for all youre help!
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