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Can someone please help. Im kind of desperate
One can imagine various points at which the line segment can be broken up. in fact, it would form a continuum up to the starting and end points.
Try and think of it like this, a triangle contained in a semi-circle
In that instance you could have the top point of the triangle anywhere along the 180 degrees of the semi-circle except at 0 and 180 degrees where you would just have a line. so at most you can create 180-2 triangles i.e. 178 different triangles
Now that is if the points of the triangle are discrete, if they are continuous (i.e. using the real number system, then the number approaches an infinity.
sorry, im here... i understand what youre saying
So, you can write your answer as follows: For the set of points where the points are from the set of integers , the number of triangles that can be created is 178.
alright... but how do i make this a probability?
simple. there is 1/178 chance when you divide up the line that one of the 178 triangles will be chosen
OH isee thanks so much!
sorry, but that answer seems to be wrong...
Im using an online math stimulator where it goves me different problems.... and it says that this answer is wrong.
Addresss of online simulator?
its on aops.com but you have to pay to access it...
Okay, @mathlete, @welshfella
hmm tricky one this for a triangle to be formed any one side must not be equal or greater than the sum of the other 2
Okay, I used a semi circle, perhaps use a full circle. count 0 and 180 once for both semi-circles only. that means 360 - 2 or 358.
yeah what? @Emeyluv99
yeah, it makes sense
Can you take a screenshot of the question and post it?
OH. i got the answer...
i used @welshfella 's idea and made some inequalities and graphed it. the answer was 1/4
which of course isnt 1/4!
theres another question i needed help on... do you think you could try to help again please?
sorry i gotta go
ok thanks for all youre help!