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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    Can someone please help. Im kind of desperate

  2. anonymous
    • one year ago
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    One can imagine various points at which the line segment can be broken up. in fact, it would form a continuum up to the starting and end points.

  3. anonymous
    • one year ago
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    Try and think of it like this, a triangle contained in a semi-circle

  4. anonymous
    • one year ago
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    |dw:1439458637345:dw|

  5. anonymous
    • one year ago
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    In that instance you could have the top point of the triangle anywhere along the 180 degrees of the semi-circle except at 0 and 180 degrees where you would just have a line. so at most you can create 180-2 triangles i.e. 178 different triangles

  6. anonymous
    • one year ago
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    Now that is if the points of the triangle are discrete, if they are continuous (i.e. using the real number system, then the number approaches an infinity.

  7. anonymous
    • one year ago
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    sorry, im here... i understand what youre saying

  8. anonymous
    • one year ago
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    So, you can write your answer as follows: For the set of points where the points are from the set of integers , the number of triangles that can be created is 178.

  9. anonymous
    • one year ago
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    alright... but how do i make this a probability?

  10. anonymous
    • one year ago
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    simple. there is 1/178 chance when you divide up the line that one of the 178 triangles will be chosen

  11. anonymous
    • one year ago
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    OH isee thanks so much!

  12. anonymous
    • one year ago
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    sorry, but that answer seems to be wrong...

  13. anonymous
    • one year ago
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    Explain

  14. anonymous
    • one year ago
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    Im using an online math stimulator where it goves me different problems.... and it says that this answer is wrong.

  15. anonymous
    • one year ago
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    Addresss of online simulator?

  16. anonymous
    • one year ago
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    its on aops.com but you have to pay to access it...

  17. anonymous
    • one year ago
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    Okay, @mathlete, @welshfella

  18. anonymous
    • one year ago
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    Try 1/3

  19. anonymous
    • one year ago
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    nope...

  20. welshfella
    • one year ago
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    hmm tricky one this for a triangle to be formed any one side must not be equal or greater than the sum of the other 2

  21. anonymous
    • one year ago
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    Okay, I used a semi circle, perhaps use a full circle. count 0 and 180 once for both semi-circles only. that means 360 - 2 or 358.

  22. anonymous
    • one year ago
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    @welshfella yeah

  23. anonymous
    • one year ago
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    yeah what? @Emeyluv99

  24. anonymous
    • one year ago
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    yeah, it makes sense

  25. anonymous
    • one year ago
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    Can you take a screenshot of the question and post it?

  26. anonymous
    • one year ago
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    OH. i got the answer...

  27. anonymous
    • one year ago
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    i used @welshfella 's idea and made some inequalities and graphed it. the answer was 1/4

  28. anonymous
    • one year ago
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    which of course isnt 1/4!

  29. anonymous
    • one year ago
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    theres another question i needed help on... do you think you could try to help again please?

  30. welshfella
    • one year ago
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    sorry i gotta go

  31. anonymous
    • one year ago
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    ok thanks for all youre help!

  32. anonymous
    • one year ago
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    next question?

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