JoannaBlackwelder
  • JoannaBlackwelder
Thermo problem attached. Please help!
Chemistry
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

JoannaBlackwelder
  • JoannaBlackwelder
Only question 2.
JoannaBlackwelder
  • JoannaBlackwelder

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

JoannaBlackwelder
  • JoannaBlackwelder
Cuanchi
  • Cuanchi
1) convert the PEL (kWel) output to kJ/h, (kJ=kW x s) kilojoules = kilowatts × seconds 2) then calculate how many mol of H2 you need to produce that kJ (1molH2/237.1kJ), this is the theoretical value if the efficiency is 100%. 3) correct this value by the efficiency EEF% ( muliply by 100/EEF) , this is the real number moles of H2 that you need to produce the PEL. 4) calculate how many kg of oil you need to produce that amount of moles of H2 5) convert the kg of oil to m3 using the value of the density DEN . density= mass/volume. m3 = L and since you already in 1) converted the kW to kJ/h (be careful to use 3600s)

Looking for something else?

Not the answer you are looking for? Search for more explanations.