## anonymous one year ago 6|6-4x|=8x+4

1. anonymous

x= 1 or x= 5/2

2. anonymous

How did you get that answer.

3. Jack1

6|6-4x|=8x+4 divide both sides by 6 |6-4x|=8/6x+4/6 now square both sides 16x^2 - 48x + 36 = (16x^2)/9 + (16x)/9 + 4/9 now make one side = 0 then solve

4. Jack1

$$\Large 6|6-4x|=8x+4$$ $$\Large |6-4x|=\frac86x+\frac46$$ $$\Large \sqrt{(6-4x)^2}=\frac86x+\frac46$$ $$\Large (~~\sqrt{(6-4x)^2}~~)^2=(~~\frac86x+\frac46~~)^2$$ $$\Large (6-4x)^2=\frac{16}9x^2 + \frac{16}9x + \frac49$$ $$\Large 16x^2 - 48x + 36=\frac{16}9x^2 + \frac{16}9x + \frac49$$ $$\Large \frac{144}9x^2 - \frac{432}9x + \frac{324}9=\frac{16}9x^2 + \frac{16}9x + \frac49$$ $$\Large \frac{128}9x^2 - \frac{448}9x + \frac{320}9=0$$ $$\Large 128x^2 - 448x + 320=0$$ $$\Large 2x^2 - 7x + 5=0$$ solve for x