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Lena772
 one year ago
Aluminum metal reacts with Iron(III) oxide to produce Iron metal and Aluminum oxide.
What mass (in grams) of Aluminum metal will react with 1.50E2 g of Iron(III) oxide?
Lena772
 one year ago
Aluminum metal reacts with Iron(III) oxide to produce Iron metal and Aluminum oxide. What mass (in grams) of Aluminum metal will react with 1.50E2 g of Iron(III) oxide?

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Lena772
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha @sammixboo @UsukiDoll @Jack1

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0\[Fe _{2}O _{3}+2Al \rightarrow Al _{2} O3+2Fe\]

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1so you wrote the formula and balanced it. the next step required is to convert the mass given to moles. after, use a molar ratio  of the moles and coefficients of each species: \(\sf \dfrac{moles~of~A}{A's~coefficient}=\dfrac{moles~of~B}{B's~coefficient}\) solve for moles of Al. Convert moles to mass.

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0What are the moles of each substance @aaronq ?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1The problem tells you the mass of Fe2O3, convert that to moles. The moles of Al are unknown, so you will be solving for them  they would be your "x"

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0(1.50E2gFe2O3 * 1 mol) / 159.69 g Fe2O3 = 0.939 mol Fe2O3

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0(0.939 mol Fe2O3 * 2 mol Al) / 1 mol Fe203 = 1.878 mol Al

Lena772
 one year ago
Best ResponseYou've already chosen the best response.01.878 mol Al *26.981g Al / 1 mol Al = 50.67g Al

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0Would 50.8 be correct considering sig figs?

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0sorry. so 50.7 is correct?
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