anonymous
  • anonymous
More problems ugh! (Just 3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What is the value of the expression \[\frac{ 3 }{ 3^{-2} }\]
anonymous
  • anonymous
@imasofty
Nnesha
  • Nnesha
\[\huge\rm \frac{ x^m }{ x^{-n} }=x^{m+n}\] exponent rule

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More answers

anonymous
  • anonymous
????
anonymous
  • anonymous
\[\frac{1}{b^{-n}}=b^n\] therefore \[\huge\frac{3}{3^{-2}}=3\times 3^2=3\times 3\times 3\]
anonymous
  • anonymous
so b.27
Nnesha
  • Nnesha
if there are same bases at the numerator and 't the denominator you should move the denominator exponent to the top |dw:1439563849463:dw|
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
what @Nnesha said
anonymous
  • anonymous
yay ty
anonymous
  • anonymous
what you are supposed to be learning is that \[\huge \frac{b^m}{b^n}=b^{m-n}\]
anonymous
  • anonymous
What value of k solves the equation? \[k ^{-5}=\frac{ 1 }{ 32 }\]
anonymous
  • anonymous
so \[\frac{3^1}{3^{-2}}=3^{1-(-2)}=3^3\]
anonymous
  • anonymous
i dont really think she understands the equations
anonymous
  • anonymous
i get it now
anonymous
  • anonymous
i am sure of it, but we can soldier on
anonymous
  • anonymous
\[k^{-5}=\frac{1}{k^5}=\frac{1}{32}\iff k^5=32\]
anonymous
  • anonymous
think of a number that when raised to the power of 5 gives 32
Nnesha
  • Nnesha
to much to think, you should write that too!
anonymous
  • anonymous
6.4?
anonymous
  • anonymous
no
anonymous
  • anonymous
she is too focused on the answer
anonymous
  • anonymous
\[6.4^5\]is way too big pick a smaller number hint: it is a whole number
anonymous
  • anonymous
oh i get it hmm
anonymous
  • anonymous
2
anonymous
  • anonymous
bingo
anonymous
  • anonymous
yay!
anonymous
  • anonymous
could u help me with 1 more
anonymous
  • anonymous
why not?
anonymous
  • anonymous
nvm i got it ill still post to see if im right. What value of m solves the equation?\[2^{m} = \frac{ 1 }{ 8 }\] 3
anonymous
  • anonymous
close
anonymous
  • anonymous
\[2^3=8\] not \(\frac{1}{8}\)
anonymous
  • anonymous
make the exponent negative
anonymous
  • anonymous
no thats the problem my answer is 3
anonymous
  • anonymous
yes i know, but 3 is not the right answer
anonymous
  • anonymous
you don't want 8 you want 1/8, i.e. the "reciprocal" to get that, make the exponent negative
anonymous
  • anonymous
-3
anonymous
  • anonymous
yes
anonymous
  • anonymous
say hi to christina perry for me
anonymous
  • anonymous
huh
anonymous
  • anonymous
"perri"
anonymous
  • anonymous
i got an 80 i passed
anonymous
  • anonymous
shoot for a 100 next time
anonymous
  • anonymous
tysm
anonymous
  • anonymous
@satellite73 make me an admin lol

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