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anonymous

  • one year ago

More problems ugh! (Just 3)

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  1. anonymous
    • one year ago
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    What is the value of the expression \[\frac{ 3 }{ 3^{-2} }\]

  2. anonymous
    • one year ago
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    @imasofty

  3. Nnesha
    • one year ago
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    \[\huge\rm \frac{ x^m }{ x^{-n} }=x^{m+n}\] exponent rule

  4. anonymous
    • one year ago
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    ????

  5. anonymous
    • one year ago
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    \[\frac{1}{b^{-n}}=b^n\] therefore \[\huge\frac{3}{3^{-2}}=3\times 3^2=3\times 3\times 3\]

  6. anonymous
    • one year ago
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    so b.27

  7. Nnesha
    • one year ago
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    if there are same bases at the numerator and 't the denominator you should move the denominator exponent to the top |dw:1439563849463:dw|

  8. anonymous
    • one year ago
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    yes it is

  9. anonymous
    • one year ago
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    what @Nnesha said

  10. anonymous
    • one year ago
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    yay ty

  11. anonymous
    • one year ago
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    what you are supposed to be learning is that \[\huge \frac{b^m}{b^n}=b^{m-n}\]

  12. anonymous
    • one year ago
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    What value of k solves the equation? \[k ^{-5}=\frac{ 1 }{ 32 }\]

  13. anonymous
    • one year ago
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    so \[\frac{3^1}{3^{-2}}=3^{1-(-2)}=3^3\]

  14. anonymous
    • one year ago
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    i dont really think she understands the equations

  15. anonymous
    • one year ago
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    i get it now

  16. anonymous
    • one year ago
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    i am sure of it, but we can soldier on

  17. anonymous
    • one year ago
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    \[k^{-5}=\frac{1}{k^5}=\frac{1}{32}\iff k^5=32\]

  18. anonymous
    • one year ago
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    think of a number that when raised to the power of 5 gives 32

  19. Nnesha
    • one year ago
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    to much to think, you should write that too!

  20. anonymous
    • one year ago
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    6.4?

  21. anonymous
    • one year ago
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    no

  22. anonymous
    • one year ago
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    she is too focused on the answer

  23. anonymous
    • one year ago
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    \[6.4^5\]is way too big pick a smaller number hint: it is a whole number

  24. anonymous
    • one year ago
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    oh i get it hmm

  25. anonymous
    • one year ago
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    2

  26. anonymous
    • one year ago
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    bingo

  27. anonymous
    • one year ago
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    yay!

  28. anonymous
    • one year ago
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    could u help me with 1 more

  29. anonymous
    • one year ago
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    why not?

  30. anonymous
    • one year ago
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    nvm i got it ill still post to see if im right. What value of m solves the equation?\[2^{m} = \frac{ 1 }{ 8 }\] 3

  31. anonymous
    • one year ago
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    close

  32. anonymous
    • one year ago
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    \[2^3=8\] not \(\frac{1}{8}\)

  33. anonymous
    • one year ago
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    make the exponent negative

  34. anonymous
    • one year ago
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    no thats the problem my answer is 3

  35. anonymous
    • one year ago
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    yes i know, but 3 is not the right answer

  36. anonymous
    • one year ago
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    you don't want 8 you want 1/8, i.e. the "reciprocal" to get that, make the exponent negative

  37. anonymous
    • one year ago
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    -3

  38. anonymous
    • one year ago
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    yes

  39. anonymous
    • one year ago
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    say hi to christina perry for me

  40. anonymous
    • one year ago
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    huh

  41. anonymous
    • one year ago
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    "perri"

  42. anonymous
    • one year ago
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    i got an 80 i passed

  43. anonymous
    • one year ago
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    shoot for a 100 next time

  44. anonymous
    • one year ago
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    tysm

  45. anonymous
    • one year ago
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    @satellite73 make me an admin lol

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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