anonymous
  • anonymous
I think I have the right answer, but I'm not sure. Is it possible if someone could just double check me? Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile, and others are not marked. The probabilities are displayed in the table below: Red Green Brown Smile 0.10 0.30 0.10 No smile 0.20 0.15 0.15 If a random candy is chosen from this bag, what is the probability that the candy was red or had no smile? 0.60 <-- What I think it is. 0.20 0.30 0.50
Mathematics
chestercat
  • chestercat
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phi
  • phi
prob red is 0.1+0.2 prob no smile is 0.20 0.15 0.15 we add (but we should *not* double count the red , no smile case) in other words 0.1 + 0.2 +0.15+0.15 = 0.6
anonymous
  • anonymous
So I'm right?
anonymous
  • anonymous
Thank you!

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pooja195
  • pooja195
lol ye thats right :) \(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\)\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Large\bf\color{Lime}{Please,\ don't\ hesitate\ to\ ask\ questions!}\)\(\Large\bf\color{magenta}{We're\ here\ to\ help!}\Large\color{magenta}{\ddot\smile}\)

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