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anonymous
 one year ago
Which graph represents the function of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 2?
A.graph of 2 x minus 4, with discontinuity at negative 1, negative 6
B.graph of 2 x minus 4, with discontinuity at 1, negative 2
C.graph of 2 x plus 2, with discontinuity at negative 1, 0
D.graph of 2 x plus 2, with discontinuity at 1, 4
anonymous
 one year ago
Which graph represents the function of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 2? A.graph of 2 x minus 4, with discontinuity at negative 1, negative 6 B.graph of 2 x minus 4, with discontinuity at 1, negative 2 C.graph of 2 x plus 2, with discontinuity at negative 1, 0 D.graph of 2 x plus 2, with discontinuity at 1, 4

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 @princeharryyy @FEARLESS_JOCEY @welshfella @Etrainx

welshfella
 one year ago
Best ResponseYou've already chosen the best response.14x^2  4x  8  2x + 2

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1this simplifies to a linear function

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1so its graph will be a straight line

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1it simplifies to 4 ( x + 1)(x  2)  2(x + 1) = 4(x  2) / 2 = 2(x  2)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1= 2x  4 where will the discontinuities be?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1 sorry theres just one discontinuity

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1although it simplifies to a linear function and the graph will be a line except, because it is a fraction there will be a point where there is no value for f(x) and it can be represented on the graph by a small open circle.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1 this is called a 'hole' in the graph This one is confusing me a little because the way to find holes is to set the factor common to top and bottom of the fraction to zero and solve for x in this case the factor is x + 1 x + 1 = 0 so x = 1 that is a hole at x = 1

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1and corresponding value of f(x) = 6 oh OK  i got confused That is the answer B
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